All categories

4 years ago

How to solve for g 10g^2+33g=9-2g^2

1 answer:

3 0

Given: 10g^2+33g=9-2g^2

Group the q^2 terms first, then the q terms, and finally the constants:

12g^2 + 33q - 9 = 0. Make sure you agree with this, or otherwise fix it.

Tools for solving quadratic equations include the following and more:

graphing
quadratic formula
completing the square

I've graphed this simplified quadratic on my TI-83 calculator and see that -3 seems to be a root. Let's check it!
________________
-3 / 12 33 -9
-36 9
---------------------
12 -3 0 Since the remainder is zero, -3 is a root and (x+3) is a factor. The other factors are 3 and (4x -1)

Then 3(4g-1)(g+3) = 0, with the result that g = 1/4 and g = -3.

Please check these roots by subst. into the original equation.

You might be interested in

A bag only contains 4 red and 6 blue marbles. What is the probability of drawing a green marble?

Paraphin [41]

Answer:

0% chance

Step-by-step explanation:

there are no green marbles

4 0

3 years ago

The Stock Market Nadia is a stockbroker. She earns 14% commission each week. Last week,

aleksklad [387]

Answer:

5,400x14%= $756 last week commission

756x12= $9,072 in 2011

Step-by-step explanation:

7 0

3 years ago

How many ml of 1:4 solution and how many ml of sterile water are needed to prepare 600 ml of 1:20 solution ?

Delvig [45]

Answer:

Approximately 143 mL of 1:4 solution and 457 mL of water

Step-by-step explanation:

A 1:4 solution has a concentration of 1/(1+4) = 1/5 or 20%.

Similarly, a 1:20 solution has a concentration of 1/(1+20) = 1/21 or 4.76%.

If x is the mL of 20% solution and y is the mL of water, then:

x + y = 600

1/5 x = 1/21 (600)

Solve:

x = 5/21 (600)

x ≈ 143

y ≈ 457

You need approximately 143 mL of 1:4 solution and 457 mL of water.

4 0

3 years ago

If g(x) = x2 – 4, find g(5). 6 О 14 21 O 29

Sladkaya [172]

$\boxed{ \sf{Answer}}$

$\sf \: g(x) = {x}^{2} - 4 \\ \\ \sf \: x = 5 \\ \\ \sf \: g(5) = {5}^{2} - 4 \\ \sf \: g(5) = 25 - 4 \\ \sf \: g(5) =\underline 2\underline1$

Answer ↦21 [Option C]

6 0

3 years ago

Read 2 more answers

The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t

Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.054.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.054\frac{54}{\sqrt{430}} = 5.35$

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

8 0

3 years ago