Answer:
See explanation
Step-by-step explanation:
Consider the sequence 10, 6, 2, -2, -4, ...
Rewrite it as
![a_1=10,\\ \\a_2=6,\\ \\a_3=2,\\ \\a_4=-2,\\ \\a_5=-6,...](https://tex.z-dn.net/?f=a_1%3D10%2C%5C%5C%20%5C%5Ca_2%3D6%2C%5C%5C%20%5C%5Ca_3%3D2%2C%5C%5C%20%5C%5Ca_4%3D-2%2C%5C%5C%20%5C%5Ca_5%3D-6%2C...)
The points on the coordinate plane are
(see attached graph).
Since
given sequence is arithmetic.
Answer:
closed, or shaded, circle is used to represent the inequalities greater than or equal to (≥) or less than or equal to (≤) . The point is part of the solution. An open circle is used for greater than (>) or less than (<). The point is not part of the solution.
For this case we have the following polynomial:
![x ^ 4 + 8x ^ 2 - 9](https://tex.z-dn.net/?f=%20x%20%5E%204%20%2B%208x%20%5E%202%20-%209%20%20)
We make the following change of variables:
![u = x ^ 2](https://tex.z-dn.net/?f=%20u%20%3D%20x%20%5E%202%20%20)
Rewriting we have
![u ^ 2 + 8u - 9](https://tex.z-dn.net/?f=%20u%20%5E%202%20%2B%208u%20-%209%20%20)
Factoring the second order polynomial we have:
![(u + 9) (u-1)](https://tex.z-dn.net/?f=%20%28u%20%2B%209%29%20%28u-1%29%20%20)
Then, returning the change we have:
![(x ^ 2 + 9) (x ^ 2-1)](https://tex.z-dn.net/?f=%20%28x%20%5E%202%20%2B%209%29%20%28x%20%5E%202-1%29%20%20)
Finally, we factor the expression in the parentheses of the second term:
![(x ^ 2 + 9) (x + 1) (x-1)](https://tex.z-dn.net/?f=%20%28x%20%5E%202%20%2B%209%29%20%28x%20%2B%201%29%20%28x-1%29%20%20)
Answer:
the completely factored form is:
![(x ^ 2 + 9) (x + 1) (x-1)](https://tex.z-dn.net/?f=%20%28x%20%5E%202%20%2B%209%29%20%28x%20%2B%201%29%20%28x-1%29%20)
Answer:
D.
Step-by-step explanation:
Each toss is independent so the probability of getting a tail is the same thE OF GETTING A HEAD - 50%^.
Answer:
Step-by-step explanation: