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2 years ago

I need help ASAP!!!!!

Mathematics

1 answer:

navik [9.2K]2 years ago

5 0

The answer is 10.8. 22-11.2 = 10.8

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ONE HUNDRED POINTS<br> a =<br><br> 4<br> 9<br> 6

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I think the answer is 9...............

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2 years ago

Reflect across the y=x. Fill in the new coordinates below:

Y_Kistochka [10]

Answer:

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2 years ago

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2 years ago

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3 years ago

Select all possible values for x in the equation x^3=375?

Helga [31]

<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

To solve the problem, we need to remember the following properties of the exponents and roots:

$a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}$

Then, we are given the expression:

$x^{3}=375$

So, finding "x", we have:

$x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}$

Hence, the possible values for x in the equation, are:

First option, $5\sqrt[3]{3}$

Second option, $\sqrt[3]{375}$

Have a nice day!

7 0

3 years ago