Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

Answer:
-6
Step-by-step explanation:
is that quizzes join lol
Step-by-step explanation:
Recall that

Therefore,

so


Hey there!
Okay let's get cracking :D
The equation is.... (2x/3) - 6 = 9
2x/3 = 15
2x = 45
<u>x = 22.5</u><u /> <----- And that is your answer!
I hope it helped!
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