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denpristay [2]
3 years ago
10

Standard printer paper has a thickness of 0.1mm. write an equation for a function that should approximately the thickness of a s

heet of paper after nn folds. f(n)=f(n)=
Mathematics
1 answer:
ladessa [460]3 years ago
4 0
Folding a paper will make it thickness become double from it before.
Unfolded paper has 1 thickness
1 times folded paper has 2 thickness
2 times folded paper has 4 thickness
3 times folded paper has 8 thickness

From here it is clear that the pattern is 2^{n}. SInce the paper is 0.1mm, then the function would be:
f(n)= 2^{n} x 0.1mm
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Answer:

The answer is D

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Abbot Tools is designing a new toolbox. The length of the toolbox will be three times its width, w, and the length of the diagon
Ilia_Sergeevich [38]

The length and width of the toolbox given the diagonal is 45 inches and 15 inches respectively.

<h3>Triangle</h3>

  • Width of the triangle = w
  • Length of the triangle = 3w
  • Diagonal = 30 inches

Hypotenuse ² = opposite ² + adjacent ²

30² = w² + (3w²)

30² = 4w²

900 = 4w²

w² = 900/4

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w = √225

w = 15

Therefore,

Width of the triangle = w

= 15 inches

Length of the triangle = 3w

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= 45 inches

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2 years ago
Arnie decides to make 3 cups of dark orange paint and 3 cups of light orange paint.
dimulka [17.4K]

The question is an illustration of equivalent ratios.

  • 3 cups of dark orange require 3 ounces of yellow  paint
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1 cup of dark orange requires

Red = 7oz

Yellow =1oz

To make 3 cups, we simply multiply by 3, because 3 \times 1 = 3

So, we have:

Red = 7oz \times 3 = 21oz

Yellow =1oz \times 3 = 3oz

2 cups of light orange require

Red =3oz

Yellow =13

To make 3 cups, we simply multiply by 1.5, because 2 \times 1.5 = 3

So, we have:

Red = 3oz \times 1.5 = 4.5oz

Yellow = 13oz \times 1.5 = 19.5oz

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5 0
2 years ago
I NEED HELP!! please show all work
PtichkaEL [24]

Take the logarithm of both sides. The base of the logarithm doesn't matter.

4^{5x} = 3^{x-2}

\implies \log 4^{5x} = \log 3^{x-2}

Drop the exponents:

\implies 5x \log 4 = (x-2) \log 3

Expand the right side:

\implies 5x \log 4 = x \log 3 - 2 \log 3

Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :

\implies 5x \log 4 - x \log 3 = - 2 \log 3

\implies x (5 \log 4 - \log 3) = - 2 \log 3

Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :

\implies \boxed{x = -\dfrac{ 2 \log 3 }{ 5 \log 4 - \log 3 }}

You can stop there, or continue simplifying the solution by using properties of logarithms:

\implies x = -\dfrac{ \log 3^2 }{ \log 4^5 - \log 3 }

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\implies \boxed{x = -\dfrac{ \log 9 }{ \log \frac{1024}3 }}

You can condense the solution further using the change-of-base identity,

\implies \boxed{x = -\log_{\frac{1024}3}9}

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Lapatulllka [165]
$995.9....................... (ignore the dots)
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3 years ago
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