Answer:
|F net| = 20.22 N
θ ≈ 19.8°
Step-by-step explanation:
F net = 15N i + 8cos(60°)N i + 8sin(60°)N j
= 15N i + 8×½N i + 8×√3/2N j
= 15N i + 4N i + 4√3N j
= 19N i + 4√3N j
|F net| = √(19²+(4√3)²) = √(361+48) = √409 ≈ 20.22N
tan(θ) = 4√3 ÷ 19 ≈ 0.36 → θ ≈ arctan(0.36) = 19.8°
Answer:
The surface area formula for a cone, given its diameter (or radius) and height, is π x (diameter / 2) 2 + π x (diameter / 2) x √ (diameter / 2) 2 + (height 2), where (diameter / 2) is the radius of the base (d = 2 x r), so another way to write it is π x radius 2 + π x radius x √ (radius 2 + (height 2)
(X+5)^2 = x^2 +10x + 25
the expression that is equivalent to
To multiply it we apply FOIL method
Multiply x with x+5 first and then we multiply 5 with x+5
Answer:
B and D
Step-by-step explanation:
