R = rides
S = sodas
6R + 3S = $21.75 —> -12R - 6S = -43.5
10R + 6S = $39.50–>10R + 6S = 39.5
Multiplying Justin’s whole equation by -2 will bring out the 6S’, so we can focus on the cost of one ride.
-2R = -4
Divide both sides by -2
So for one ride, it would cost $2.
To find the cost for one soda, we plug in the cost for a ride.
6(2) + 3S = $21.75
12 + 3S = $21.75
3S = $9.75
So for one soda, it would cost $3.25.
Answer:
B.-38
Step-by-step explanation:
2x - 18 = y ...(1)
x = -10 (Given)
Now,
Put the value of x in equation (1) we get,
2(-10) - 18 = y
-20 - 18 = y
-38 = y
<em><u>y = -38</u></em>
Thus, the value of y is -38
Answer: the number of adult and student tickets sold are (45, 29)
Step-by-step explanation:
Let x represent the number of adult tickets that were sold.
Let y represent the number of student tickets that were sold.
On Wednesday, a total of 74 tickets were sold. This means that
x + y = 74
x = 74 - y- - - - - - - - - - - - - - 1
If adult tickets are sold for $15 and student tickets are sold for $11 and the money collected was $994, it means that
15x + 11y = 994- - - - - - - - - - - - - - 2
Substituting equation 1 into equation 2, it becomes
15(74 - y) + 11y = 994
1110 - 15y + 11y = 994
- 15y + 11y = 994 - 1110
- 4y = - 116
y = - 116/ - 4
y = 29
Substituting y = 29 into equation 1, it becomes
x = 74 - 29 = 45
19 + 52 = 81. 81 - 1 x 5 = 76.
