Answer: See below.
Step-by-step explanation:
The formatting is likely incorrect for these two options:
y=(x−1)2, and
y = ( x − − 1 ) 2
I'll assume they were meant to be:
y=(x−1)^2, and
y = ( x + 1 )^2
In this case they would be non-linear, since y depends on the value of 
Use a "^" sign to indicate raised to a power: x^2 means
.
y=(x−1)2 means y = 2x - 2
y=(x−1)^2 means y = 
Answer:

Step-by-step explanation:
Given
--- rate of hard disk drives failure
--- number of hard disk drives
<em>See comment for complete question</em>
Required

First, calculate the probability that the none of the 4 selected is working;



Using the complement rule, the probability that at least 1 is working is:

This gives:


Answer:
Expected revenue from the single trip is $ 13.14
Step-by-step explanation:
y
p(x,y) 0 1 2 g(x)
x 0 0.025 0.015 0.010 0.05
1 0.050 0.030 0.020 0.1
2 0.115 0.075 0.050 0.24
3 0.150 0.090 0.060 0.3
<u>4 0.100 0.060 0.040 0.2 </u>
h(y) 0.325 0.27 0.18
E (x+Y) = E(X) +E(Y)
E(X)= ∑ xi g(x)i
= ( 0*0.05) + (1*0.1) + (2* 0.24) + (3*0.3) + (4*0.2)
= 0 + 0.1+ 0.48 + 0.9+0.8
=2.28
E(Y)= ∑yi h(y)
= (0* 0.325) + (1*0.27) + (2*0.18)
= 0 +0.27+ 0.36
= 0.63
E (x+Y) = E(X) +E(Y)
= 2.28 + 0.63
= 2.91
But the equation is 3x+ 10y
E(3x+ 10y)= 3E(x) + 10 E(y)
= 3(2.28) + 10 (0.63)
= 6.84 +6.3
= 13.14
Expected revenue from the single trip is $ 13.14
Answer:
So it looks like the given zeros are 2i and -3. We have to work backwards.
x = -3 and x = 2i
For -3, we know that out factored form before would have been x + 3
For 2i, that means we took the square root of negative number because it is imaginary. So that means out factored for x2 + 4
So if we put these together:
(x2 + 4)(x + 3) = x3 + 3x2 + 4x + 12
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Step-by-step explanation: