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marissa [1.9K]
3 years ago
15

Calculate the following percentage A) $200 of $410

Mathematics
1 answer:
Maslowich3 years ago
7 0
Answer: 48.781%
Plug it into a percentage calculator
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Equations
sergij07 [2.7K]

Answer:

2x+12=24

first you subtract 12 from both sides

2x+12=24

-12. -12

The 12-12 should cancel itself, the rest of the equation you bring down to get

2x=12 (because 24-12=12)


Now you have 2x=12.
you then divide 2x by both sides.

2x=12

/2x=/2x

The 2x/2x cancels itself out so you then solve for 12/2x.

For this you just divide 12/2 which is 6!

x= 6 is your final answer.
to check this equation you can plug your number back into x to see if it is true! 2(6)+12=24.
6 times 2 is 12 and 12+12 is 24 so your answer (6) is true!


hope this helps! :D

4 0
2 years ago
Read 2 more answers
PLEASE HELP HURRY!!!
Akimi4 [234]

Answer:

C

Step-by-step explanation:

consistently goes down by 3.2 for the y value

5 0
3 years ago
Wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba wooba
Nostrana [21]

Answer:

wooowooowowowowowowowowow

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Graphs of Function,
andrew-mc [135]

Answer:

A function is increasing when the gradient is positive

A function is decreasing when the gradient is negative

<u>Question 7</u>

If you draw a tangent to the curve in the interval x < -2 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve in the interval x > -2 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -2 will be zero.

The function is increasing when x < -2

(- \infty,-2)

The function is decreasing when x > -2

(-2, \infty)

<u>Additional information</u>

We can actually determine the intervals where the function is increasing and decreasing by differentiating the function.

The equation of this graph is:

f(x)=-2x^2-8x-8

\implies f'(x)=-4x-8

The function is increasing when f'(x) > 0

\implies -4x-8 > 0

\implies -4x > 8

\implies x < -2

The function is decreasing when f'(x) < 0

\implies -4x-8 < 0

\implies -4x < 8

\implies x > -2

This concurs with the observations made from the graph.

<u>Question 8</u>

This is a straight line graph. The gradient is negative, so:

The function is decreasing for all real values of x

(- \infty,+ \infty)

But if they want the interval for the grid only, it would be -4 ≤ x ≤ 1

[-4,1]

<u>Question 9</u>

If you draw a tangent to the curve in the interval x < -1 then the tangent will have a negative gradient, and so the function is decreasing in this interval.

If you draw a tangent to the curve in the interval x > -1 then the tangent will have a positive gradient, and so the function is increasing in this interval.

If you draw a tangent to the curve at the vertex of the parabola, it will be a horizontal line, and so the gradient at x = -1 will be zero.

The function is decreasing when x < -1

(- \infty,-1)

The function is increasing when x > -1

(-1, \infty)

5 0
2 years ago
Helppp meee pleaseeee guysss?!!!??!?
RUDIKE [14]

Answer:

A. -1≤x≤6

Step-by-step explanation:

  • 6≥ x² - 5x
  • x² - 5x -6 ≤ 0
  • (x-6)(x+1) ≤ 0
  • x - 6 ≤ 0 ⇒ x ≤ 6
  • x + 1 ≥ 0 ⇒ x ≥ -1
  • -1 ≤ x ≤ 6

Choice A is the answer

7 0
3 years ago
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