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Phoenix [80]
3 years ago
15

one evening 1500 concert tickets were sold for the Jazz Fest. Tickets cost $30 for covered pavillion seats and $10 for lawn seat

. Total reciepts were $27,000. How many of each type of ticket were sold?'
Mathematics
1 answer:
snow_lady [41]3 years ago
6 0
x-number\ of\ tickets\ for\ pavilion\\1500-x-number\ of\ tickets\ for\ lawn\\\\30x+10(1500-x)=27000\\30x+15000-10x=27000\\30x-10x=27000-15000\\20x=12000\ \ \ \ \ \ \ \ |:20\\\\x=600\\1500-600=900
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A bookstore had 81 copies of a magazine. Yesterday the bookstore sold
olga2289 [7]

Answer:

The question is unclear, but if the book store sold 9 copies total, they sold 2 yesterday.

Step-by-step explanation:

I am not sure how many copies were sold in total but here is how you can solve it- Get the total amount of copies and subtract the number of copies sold in total. Then get the difference and subtract 7 from it. The difference is your answer.

7 0
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Leo reads 14 pages in 1/3 hourWhat is the unit rate for pages per hour
pogonyaev

To determine the unit rate of pages, that is, the number of pages Leo reads in one hour you can use cross multiplication

1/3h _____14 pages

1h______x pages

\begin{gathered} \frac{14}{\frac{1}{3}}=\frac{x}{1} \\ 14\cdot3=x \\ x=42 \end{gathered}

Leo reads 42pages/hour

7 0
1 year ago
What is one fourth of one ton HELP
Alekssandra [29.7K]
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7 0
3 years ago
Read 2 more answers
Tan(2 sin^-1 0.4)<br> Find the Exact value
stiv31 [10]

Answer:

tan(2u)=[4sqrt(21)]/[17]

Step-by-step explanation:

Let u=arcsin(0.4)

tan(2u)=sin(2u)/cos(2u)

tan(2u)=[2sin(u)cos(u)]/[cos^2(u)-sin^2(u)]

If u=arcsin(0.4), then sin(u)=0.4

By the Pythagorean Identity, cos^2(u)+sin^2(u)=1, we have cos^2(u)=1-sin^2(u)=1-(0.4)^2=1-0.16=0.84.

This also implies cos(u)=sqrt(0.84) since cosine is positive.

Plug in values:

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.84-0.16]

tan(2u)=[2(0.4)(sqrt(0.84)]/[0.68]

tan(2u)=[(0.4)(sqrt(0.84)]/[0.34]

tan(2u)=[(40)(sqrt(0.84)]/[34]

tan(2u)=[(20)(sqrt(0.84)]/[17]

Note:

0.84=0.04(21)

So the principal square root of 0.04 is 0.2

Sqrt(0.84)=0.2sqrt(21).

tan(2u)=[(20)(0.2)(sqrt(21)]/[17]

tan(2u)=[(20)(2)sqrt(21)]/[170]

tan(2u)=[(2)(2)sqrt(21)]/[17]

tan(2u)=[4sqrt(21)]/[17]

7 0
3 years ago
The archway of the main entrance of a university is modeled by the quadratic equation
Scilla [17]

Answer:

B. (1,5) and (5.25, 3.94)

Step-by-step explanation:

The answer is where the 2 equations intersect.

We need to solve the following system of equations:

y = -x^2 + 6x

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From the second equation:

x = 21 - 4y

Plug this into the first equation:

y = -(21 - 4y)^2 + 6(21 - 4y)

y = -(441 - 168y + 16y^2)+  126 - 24y

y = -441 + 168y - 16y^2 +  126 - 24y

16y^2 + y - 168y + 24y + 441 - 126 = 0

16y^2 - 143y + 315 = 0

y = [-(-143) +/- sqrt ((-143)^2 - 4 * 16 * 315)]/ (2*16)

y = 5, 3.938

When y = 5:

x = 21 - 4(5) = 1

When y = 3.938

x = 21 - 4(3.938) = 5.25.

3 0
3 years ago
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