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4 years ago

3b-4/2 = c (solve for b) please show work, thanks!

Mathematics

1 answer:

liq [111]4 years ago

6 0

Answer:

Step-by-step explanation:

1. multiply both sides by 2

2. add 4 to both sides

3b=2c+4

3. divide both sides by 3

b= $\frac{2b+4}{3}$

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Each letter of the word "thunderstorm" has been written on a separate slip of paper and put into a box. Find the probability of

xxTIMURxx [149]

SOLUTION

From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.

This means the probability of selecting t and r.

That is

$P(t)\times P(r)$

There are 12 letters (total outcomes). And there are 2r and 2t.

So probability becomes

$\begin{gathered} \frac{possible\text{ outcome}}{\text{total outcome }} \\ P(t)=\frac{2}{12} \\ P(r)=\frac{2}{12} \\ P(t)\times P(r)=\frac{2}{12}\times\frac{2}{12} \\ =\frac{1}{6}\times\frac{1}{6} \\ =\frac{1}{36} \end{gathered}$

Hence the answer is

$\frac{1}{36}$

7 0

1 year ago

The inequality of the most people that can be seated in the auditorium

WINSTONCH [101]

Let x be the number of people that can be seated.

The value of x is some number 0 or greater, such that this number is a whole number (we can't have half a person). This means that $x \ge 0$ which is the same as saying $0 \le x$

The instructions state that we can seat up to 1200 people. This is the max capacity. We can't go over this amount. So we will also have $x \le 1200$ indicating that x can be less than 1200 or equal to 1200.

So putting the two inequalities together, we get $0 \le x \le 1200$

Note: if you haven't learned about compound inequalities yet, then the teacher may only want $x \le 1200$ as the answer.

3 0

4 years ago

Drawing Conclusions

maksim [4K]

Answer:

Some of the Exponents = -2 that is true, not 2.

Step-by-step explanation:

Let's check one at a time.

(a)The 6 without an exponent is equivalent to the 6 having a 0 exponent.

$6^{0} =1$ and $6^{1}$ = 6 (no exponent. 6 $\neq$ 1 therefore this statement is False.

(b)The sum of the exponents is -2.

let's check , if the base is same we can add the exponents that is the exponent rule.(well established).

if we add exponents in the given expression we get.

$6^{1} 6^{0} 6^{3} =6^{1+0+(-3)} =6^{-2}$ , therefore we can see that the sum of the exponents = -2 this is true.

(c) An equivalent expression is 65.6-7, lets evaluate our above expression, it is equal to $\frac{1}{36}$ which we can see that $\frac{1}{36} \neq 65.6-7$ ,therefore this statement is false as well.