Question

PLEASE HELP. WILL GIVE BRAINLIEST. :)

Answer 1

Answer: Using the proportion beteween the sides of the similar triangles, the distance between the endpoints of the beams P and Q is 3.2 inches.

Option a. 3.2 inches

Solution

PR=3.7 inches; CR=5.6 inches; AC=4.9 inches

As the two triangles QRP and ARC are similar, their sides must be proportionals, then:

PQ/AC=PR/CR=QR/AR

Replacing the given values in the proportion above:

PQ/(4.9 inches)=(3.7 inches)/(5.6 inches)=QR/AR

PQ/(4.9 inches)=3.7/5.6

Solving for PQ: Multiplying both sides of the equation by 4.9 inches:

(4.9 inches)[PQ/(4.9 inches)]=(4.9 inches)(3.7/5.6)

PQ=(4.9)(3.7)/5.6 inches

PQ=18.13/5.6 inches

PQ=3.2375 inches

Rounding to one decimal place:

PQ=3.2 inches

Answer 2

Answer:

Option A. 3.2 inches

Step-by-step explanation:

As shown in the figure it is given that Δ QRP and Δ ARC are two similar triangles.

Given lengths are mPR = 3.7 inches

mCR = 5.6 inches

Distance between A and C is = 4.9 inches

By the theorem of similar triangles in Δ PQR and Δ ACR

$\frac{PQ}{AC}=\frac{PR}{RC}$

$\frac{PQ}{4.9}=\frac{3.7}{5.6}$

$PQ=\frac{(4.9)(3.7)}{(5.6)}=\frac{18.13}{5.6}=3.2$

Therefore Option A. mPQ = 3.2 inches is the answer