Answer:

Step-by-step explanation:
Given



<em>Translation: 3 units left and 1 unit right</em>
Required
Determine the new coordinates of B
Write out the coordinates of B


When a function is shifted to the left, we have to subtract the unit from the x value of the function;
<em>Shifting by 3 units left, the new x becomes </em>
<em />
<em />
<em />
<em />
<em />
When a function is shifted upward, we have to add the unit to the y value of the function;
<em>Shifting by 1 unit up, the new y becomes </em>


Hence, the new coordinates of B is

Answer:
x = 2 and x = 4
Step-by-step explanation:
The solution of the given equation is shown on the graph
<u>There are two intercepts with coordinates of</u>
<u>The x-coordinates are </u>
Correct option is 3 or C.
Answer:
6
Step-by-step explanation:
Range is set of all y-values. To find a range of graphed function, we need to know that range starts from the minimum value of graph to maximum value. That's because the minimum value is the least value that you can get by substituting the domain and the maximum value is the largest value that you can get by substituting the domain as well.
Now we don't talk about domain here, we talk about range. See the attachment! You are supposed to focus on y-axis, plane or vertical line. See how the minimum value of function is the negative value while the maximum value is positive.
That means any ranges that don't contain the negative values are cleared out. (Hence A and C choices are wrong.)
Next, range being set of all real numbers mean that graphed functions don't have maximum value or minimum value (We can say that both max and min are infinite.)
Take a look at line graph as an example of range being set of all real numbers, or cubic function.
Answer/Conclusion
- The range exists from negative value which is -9 to the maximum value which is 5.
- That means the range is -9<=y<=5
Answer:
C. 
General Formulas and Concepts:
<u>Calculus</u>
- Mean Value Theorem (MVT) - If f is continuous on interval [a, b], then there is a c∈[a, b] such that

- MVT is also Average Value
Step-by-step explanation:
<u>Step 1: Define</u>

f'(c) = 20
Interval [1, b]
<u>Step 2: Check/Identify</u>
Function [1, b] is continuous.
Derivative [1, b] is continuous.
∴ There exists a c∈[1, b] such that 
<u>Step 3: Mean Value Theorem</u>
- Substitute:

- Rewrite:

And we have our final answer!