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Hoochie [10]
3 years ago
6

I need help with this please...

Mathematics
2 answers:
Luda [366]3 years ago
5 0
Answer:
I think it should be 56
DENIUS [597]3 years ago
3 0
Minimum the answer should be 34
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I need help please!!!
e-lub [12.9K]
There is no distinct pattern, the scatter plot would be up down and spread apart, nothing really correlated.

3 0
2 years ago
In the adjoining figure, the parallel lines are marked by arrow lines. The value of angle 1 is:
dlinn [17]

Answer:

20°

Step-by-step explanation:

40°, 70° and 90° are the measures of the three angles of the quadrilateral.

Measure of fourth angle of the Quadrilateral

= 360° - (40° + 70° + 90°)

= 360° - 200°

= 160°

Measure of angle 1 will be equal to the measure of the linear pair angle of 160° as they are corresponding angles.

Thus,

m\angle 1 = 180\degree- 160\degree

\implies\huge\purple{\boxed{ m\angle 1 = 20\degree}}

Alternate method:

m\angle 1 = 180\degree- [360\degree-(40\degree+70\degree+90\degree)]

\implies m\angle 1 = 180\degree- [360\degree-200\degree]

\implies m\angle 1 = 180\degree- 160\degree

\implies m\angle 1 = 20\degree

6 0
3 years ago
Read 2 more answers
The sum of first 'n' terms. Sn of a particular Arithmetic Progression is given by Sn=12n-2n^2. Find the first term and the commo
Vitek1552 [10]

Answer:

d=-4 and a=10

Step-by-step explanation:

The sum of a arithmetic sequence is given by (n/2)*(2a+(n-1)d). Comparing coefficients with the given Sn, we have; a-d/2=12 and d/2=-2, d=-4 and a=10.

4 0
3 years ago
A cat had a litter of 5 kittens. If each sex is equally likely, what is the probability that 3 or less were female kittens?
ASHA 777 [7]

Answer:

0.8125

Step-by-step explanation:

In this question, we are tasked with calculating the probability that 3 or less of her kittens were female.

Since each bsex is of likely probability, the probability of a male kitten = probability of a female kitten = 0.5

Now to calculate for 3 or less female kitten we are calcualting P(f) ≤ 3

In each case, we use the Bernoulli approximation

P(f) ≤ 3 = 5C3 m^{2} f^{3} + 5C2 m^{2}  f^{3} + 5C1 m^{4}  f + 5C0 m^{5}  f^{0}

Where m is the probability of a male kitten and f is the probability of having a female kitten with both values = 0.5

P(f) ≤ 3 =(0.3125) + (0.3125) + (0.15625) + (0.03125) = 0.8125

8 0
3 years ago
$30.50 - $17.79= what<br> Solve this problem in two diffrent ways (5th grade math)
puteri [66]
$30.50-$17.79 is $12.71. I hope that helps you :)
4 0
4 years ago
Read 2 more answers
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