1 + 2^1 = 3
3 + 2^2 = 7
7 + 2^3 = 15
15 + 2^4 = 31
31 + 2^5 = 63
63 + 2^6 = 127
so the next two terms in the sequence 1, 3, 7, 15, 31, is 63 and 127.
Answer:
By breaking it up in shapes
Step-by-step explanation:
I annotated your photo and it's attached below :) that's an example on how to break shapes into easier parts. So yeah
(6,-8)(6,8)
d = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((6 - 6)^2 + (8 - (-8)^2)
d = sqrt ((0^2 + 16^2)
d = sqrt 16^2
d = sqrt 256
d = 16 <==
Answer:
D
Step-by-step explanation:
I am a wiz
