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2 years ago

Write a polynomial that has the lowest degree, a leading coefficient of 2, and 1/2 and 3 + √5 as roots?

1 answer:

3 0

$2\left(x-\dfrac{1}{2}\right)(x-(3+\sqrt5))=\\
(2x-1)(x-3-\sqrt5)=\\
2x^2-6x-2\sqrt5x -x+3+\sqrt5=\\
2x^2-(7+2\sqrt5)x+3+\sqrt5$

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2 years ago

Given that 5 x − 3 y = 32 Find y when x = 4

ollegr [7]

Answer:

Solution,

X=4

Now,

 $5x - 3y = 32 \\ or \: 5 \times x - 3y = 32 \\ or \: 5 \times 4 - 3y = 32 \\ or \: 20 - 3y = 32 \\ or \: - 3y = 32 - 20 \\ or \: - 3y = 12 \\ or \: y = - \frac{12}{ 3} \\ y = - 4$ 

Hope this helps...

Good luck on your assignment..

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3 years ago

Read 2 more answers

If x is a number that is 7 more than y, how do you express x as a function of y

Soloha48 [4]

$x=y+7$
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2 years ago

Whats 1/7 + 3/4 ? Please help me?

Katen [24]

Answer:

25/28

Step-by-step explanation:

28 is the greatest common factor, found by multiplying 7 by 4 (the denominators)

1/7 = 4/28

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2 years ago

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In a geometric sequence, if a3 = ‒5 and a6 = 40, determine a1, r, and an. Then write the first three terms of the sequence.

Tresset [83]

$a_4=ra_3$
$a_5=ra_4=r^2a_3$
$a_6=ra_5=r^3a_3$

$40=-5r^3\implies r^3=-8\implies r=-2$

$a_3=ra_2=r^2a_1$

$-5=(-2)^2a_1\implies a_1=-\dfrac54$

You know the first and third terms, $a_1$ and $a_3$ , so you just need to find the second term $a_2$ :

$a_2=ra_1\implies a_2=-2\left(-\dfrac54\right)=\dfrac52$

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2 years ago