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zmey [24]
3 years ago
8

Determine if the lines are parallel, perpendicular, or neither y=5 and y =-1

Mathematics
2 answers:
valkas [14]3 years ago
6 0
The are parallel to each other because the are both straight horizontal lines
Anna35 [415]3 years ago
4 0
<span> y = 5 and y = -1 is a parallel line .
They both line on the y - axis .
( 0,5 ) and ( 0,-1 ) </span>
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The product of a number and ten is twelve more than the product of the number and five-eighths.
ra1l [238]
Let the unknown number be x.

Given,

10 * x = 12 +  \frac{5}{8}  * x

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3 years ago
Manuel pays $ 500 per year fees to his homeowner's association. Next year, the association is increasing its fee by 5%
tigry1 [53]

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3 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
3 years ago
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