Question

Write an equation of a line that is parallel to the line whose equation is 3y=x+6 and that passes through the point (-3,4).

Answer 1

The standard form of this equation is

$y=\frac{1}{3}x+2$

The slope of two parallel lines i the same, so the slope of the line we're looking for is also $\frac{1}{3}$

Since the line passes through $(-3,4)$, the equation is:

$(y-4)=\frac{1}{3}(x+3)$

$\boxed{y=\frac{1}{3}x+5}$