I'm guessing on the make up of the matrices.
First off let's look at [C][F].
[C]=
[F]=
[C][F]=
where each element of [C][F] comes from multiplying a row of [C] with a column of [F].
Example: First element is product of first row and first column.
.
.
.
Now that we have [C][F], we can subtract it from [B], element by element,
[B]-[C][F]=
[B]-[C][F]=
.
.
.
If this is not how the matrices look,please re-state the problem and be more specific about the make up of the matrices (rows x columns).
Here's an example.
[A] is a 2x2 matrix. A=[1,2,3,4].
The assumption is that [A] looks like this,
[A]=
[B] is a 3x2 matrix. B=[5,6,7,8,9,10]
[B]=
Answer:
I think it's 1/16
Step-by-step explanation:
Answer:
The confidence interval is 6.6<μ<6.8.
Step-by-step explanation:
We have:
Number of observations = 601
Mean = 6.7
Standard deviation σ = 1.5
The z-score for a 95% confidence interval is 1.96.
The limits of the confidence interval can be calculated as
![X \pm z*\frac{\sigma}{\sqrt{n}}\\\\LL=X-z*\frac{\sigma}{\sqrt{n}}=6.7-1.96*\frac{1.5}{\sqrt{601} } =6.7-0.1199=6.6\\\\UL=X+z*\frac{\sigma}{\sqrt{n}}=6.7+1.96*\frac{1.5}{\sqrt{601} } =6.7+0.1199=6.8](https://tex.z-dn.net/?f=X%20%5Cpm%20z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%5C%5C%5C%5CLL%3DX-z%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%3D6.7-1.96%2A%5Cfrac%7B1.5%7D%7B%5Csqrt%7B601%7D%20%7D%20%3D6.7-0.1199%3D6.6%5C%5C%5C%5CUL%3DX%2Bz%2A%5Cfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D%3D6.7%2B1.96%2A%5Cfrac%7B1.5%7D%7B%5Csqrt%7B601%7D%20%7D%20%3D6.7%2B0.1199%3D6.8)
The confidence interval is 6.6<μ<6.8.
Answer:
-1,3
Step-by-step explanation:
1 left and 3 up