Answer:
The four critical factors to planning a successful project
Explanation:
Due to it's typically massive size, WAN's are almost always slower then a LAN. The further the distance, the slower the network. One of the big disadvantages to having a WAN is the cost it can incur. Having a private WAN can be expensive.
Explanation:
"Select vendor_name as Vendor_Name,
default_account_number as Default_Account_No ,
account_description as Account_Description
From Vendors v, General_Ledger_Accounts ledger
where (add the join condition here)
Order by account_description, vendor_name"
Note: In the above statement, include the alias name appropriately and then execute the query
The "select statement" should contain the list of columns to be displayed
"From statement" should contain the name of the table from which data needs to be fetched.
"Where clause" defines the relationship as well the condition that needs to be executed
"Order by clause" defines the sorting mechanism with the relevant field
Answer:
Explanation:
1. Write a program that declares an array named alpha with 50 components of the type double. Initialize the array so that the first 25 components are equal to the square of the counter (or index) variable and the last 25 components are equal to three times the index variable.
double alpha[50];
for (int i=0;i<25;i++)
{
alpha[i]=i*i;
alpha[i+25]=(i+25)*3;
}
2. Output the array so that exactly ten elements per line are printed.
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
3. Run your program again, but this time change the code so that the array is filled with random numbers between 1 and 100.
double alpha[50];
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
}
for (int i=0;i<50;i++)
{
cout<<i+1<<". "<<alpha[i]<<" ";
if (((i+1)%10)==0)
{
cout<<endl;
}
}
4. Write the code that computes and prints the average of elements of the array.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
temp+=alpha[i];
}
cout<<"Average :"<<(temp/50);
5. Write the code that that prints out how many of the elements are EXACTLY equal to 100.
double alpha[50],temp=0;
for (int i=0;i<50;i++)
{
alpha[i]=rand()%101;
if(alpha[i]==100)
{
temp++;
}
}
cout<<"Elements Exacctly 100 :"<<temp;
Please note: If you put each of above code to the place below comment it will run perfectly after compiling
#include <iostream>
using namespace std;
int main()
{
// If you put each of above code here it will run perfectly after compiling
return 0;
}
Answer:
attenuation
Explanation:
Based on the information provided within the question it can be said that the phenomenon that is being described in this scenario is known as attenuation. In the context of physics, this refers to the gradual loss of intensity of something when traveling through a medium. Which in this case would be the data signals travelling through the cables.
