It can be useful to have a mentor because they will help you

What is the function of the NOS? Select all that apply.

Zigmanuir [339]

Answer:

.network management

Explanation:

pls need brainliest

3 0

2 years ago

Read 2 more answers

5. Create a variety of test cases focusing on the sorting algorithm, such as the final element is the smallest, the entire set i

andrew11 [14]

Answer:

// C code

// This code will compute the values of the sales ticket sales for concerts

#include <stdio.h>

#define MAXN 100 // max characters in a group/concert name

#define MAXG 50 // max concerts/groups

#define MAXC 3 //max categories

char group [MAXG][MAXN];

int fans [MAXG][MAXC];

float prices [MAXC];

float sales [MAXG];

int count = 0;

void printArray () {

printf ("%15s%5s%5s%5s%10s\n",

"Concert", "s1", "s2", "s3","Sales");

for (int i = 0; i < count; i++) {

printf ("%15s", group [i]);

for (int j = 0; j < MAXC; j++) {

printf ("%5d", fans[i][j]);

} // end for each category

printf ("%10.2f\n", sales [i]);

} // end for each group

} // end function printArray

void computeSales () {

for (int i = 0; i < count; i++) {

sales [i] = 0;

for (int j = 0; j < MAXC; j++) {

sales [i] += prices [j] * fans [i][j];

} // end for each category

} // end for each group

} // end function computeSales

// ***** totalSales ****

void totalSales()

{

float tsales;

for(int i = 0; i <= MAXC; i++){

tsales += sales [i];

}

printf("\n\t\tThe total sales are: $%.2f\n",tsales);

}

// ***********************************

void switchRows (int m, int n) {

char tc;

int ti;

float v;

// printf ("Switching %d with %d\n", m, n);

for (int i = 0; i < MAXN; i++) {

tc = group [m][i];

group [m][i] = group [n][i];

group [n][i] = tc;

} // end for each character in a group name

for (int i = 0; i < MAXC; i++) {

ti = fans [m][i];

fans [m][i] = fans [n][i];

fans [n][i] = ti;

} // end for each fan category

v = sales [m];

sales [m] = sales [n];

sales [n] = v;

} // end switch

int findMinSales (int m) {

float min = sales [m];

int target = m;

for (int i = m+1; i < count; i++)

if (sales [i] < min) {

min = sales [i];

target = i;

} // end new max found

return target;

} // end function findMinSales

void sortBySales () {

int target;

for (int i = 0; i < count; i++) {

target = findMinSales (i);

if (target > i)

switchRows (i, target);

} // for each concert

} // end function sortBySales

//**********sort by fans*************

int minFans (int b) {

float min = fans [b][0];

int target = b;

for (int i = b; i < count; i++)

if (fans [i][0] < min) {

min = fans [i][0];

target = i;

} // end new max found

return target;

}

void sortByFans () {

int target = 0;

//int result;

for (int i = 0; i < count; i++) {

target = minFans(i);

if (target > i)

//result = target;

switchRows (i,target);

}

//********************************

void getData () {

// for (int i = 0; i < MAXG; i++) sales [i] = 0;

printf ("\nEnter ticket prices in each of %d cateogories: ", MAXC);

for (int i = 0; i < MAXC; i++)

scanf ("%f", &prices [i]);

printf ("-- Enter group and fans in %d categories\n", MAXC);

printf (" . to finish entries:\n");

for (int i = 0; i < MAXG; i++) {

scanf ("%s", group[i]);

if (group [i][0] == '.')

break;

count++;

for (int j = 0; j < MAXC; j++)

scanf ("%d", &fans[i][j]);

} // end for each group

} // end function getData

int main(void) {

getData ();

computeSales ();

printArray ();

printf ("\n --- Sorted sales ---\n");

sortBySales ();

printArray ();

totalSales ();

printf("--- sorted by fans ---\n");

sortByFans ();

printArray ();

totalSales ();

printf("\t\t ... Bye ...\n");

return 0;

}

7 0

2 years ago

Where do today's computers store almost all motherboard configuration data?

sergij07 [2.7K]

In the mother board of the back door next to the restroom 5 steps left

3 0

2 years ago

Part of the central processing unit

AveGali [126]

Answer:

Explanation:

The arithmetic logic unit (ALU) performs mathematical, logical, and decision operations. It can be divided into the arithmetic unit (responsible for addition, subtraction, multiplication and division). And logic unit (responsible for comparing, selecting, matching and merging different data or information). The power and efficiency of the CPU depends on the design of the ALU.

Next up is the control unit (CU) which directs all the processor’s operations. It’s where the CPU reads and interprets requests from memory and transforms them into a series of signals (binary). Then it sends the operation to various parts of the laptop as instructed. The CU calls the ALU to perform the necessary calculations. It also coordinates all input/output devices to transfer or receive instructions.

The main job of the memory unit is to store data or instructions and intermediate results. It’s divided into primary memory and secondary memory to supply data to other units of the CPU. It allows the CPU to perform functions requested by programs like the operating system without having to ask RAM.

Another element of the CPU not depicted in the diagram is transistors. To carry out calculations, binary information (ones and zeros) is stored in these microscopic switches. They control the flow of electricity depending on whether the switch is ON or OFF. Signals turn off and on different combinations of transistors to perform calculations. A very thin silicon chip can contain several hundred million transistors.

8 0

2 years ago

1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s

konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0

2 years ago