Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
I think the answer is 3 :))
Answer:
27
Step-by-step explanation:
Let :
Number of 40¢ = x
Number of 22¢ = 4x + 3
Total stamp value = $8.34 = (8.34 * 100) = 834¢
40¢x + 22¢(4x + 3) = 834¢
40x + 88x + 66 = 834
128x = 834 - 66
128x = 768
x = 768 / 128
x = 6
Number of 22¢ stamp:
4(6) + 3 = 24 + 3 = 27
Answer:
The length ot rectangle is 3 units.
Step-by-step explanation:
The formula for perimeter is P = 2l + 2w and the area is A = l×w. Assuming that the perimeter and area have the same values so you have to compare it :
