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Vlada [557]
3 years ago
13

Mrs. Johnson is here today to receive an intercostal nerve block to mitigate the debilitating pain of her malignancy. Her cancer

has metastasized to her bones in her thoracic spine. What ICD-10-CM codes are reported?a.M54.6, C79.51, C80.1b.C79.51, G89.3, C80.1c.G89.3, C79.51, C80.1d.C79.51, G89.3, M54.6, C80.1
Computers and Technology
1 answer:
Furkat [3]3 years ago
5 0

Answer:

The correct answer is:

a. M54.6, C79.51, C80.1

Explanation:

-  M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.

- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.

Malignant neoplasm of anus, unspecified

Neoplasm related pain (acute) (chronic)

Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

Malignant (primary) neoplasm, unspecified

- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.

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your company decides to implement a RAID-5 array on several file servers. Which feature is provided by this deployment
Novay_Z [31]

Answer:

High availability

Explanation:

RAID-5 array is defined as a redundant array for independent disk configuration which makes use of the disk striping with the parity. It consists of a minimum three disk drives and it uses the data striping and the parity data to provide the redundancy.

RAID 5 is a powerful tool to ensure integrity of the data. It provides both performance as well as security to the data.

In the context, "high availability" is the feature that is provided by the deployment of RAID 5 array on the several file services.

4 0
2 years ago
In this lab, you complete a prewritten C++ program that calculates an employee’s productivity bonus and prints the employee’s na
Bas_tet [7]

Answer:

The answer to this question is given below in the explanation section

Explanation:

    The formula for productivity socre is      

 productivity score = ((transaction dollar value/no of transaction)/no of shift)

Productivity Score Bonus  is:  

<=30 $50

31–69 $75

70–199 $100

>= 200 $200

........................................................................................................................................

the code is given below

........................................................................................................................................

#include <iostream>

using namespace std;

int main()

{

   string firstName;

   string lastName;

   int noOfShift;

   int noOfTransaction;

   int transactionDollarValue;

   int productivityScore;

   int bonus;

   

   cout<<"Employee’s first name: ";

   cin>>firstName;

   cout<<"Employee's last name: ";

   cin>>lastName;

   cout<<"Number of shifts:";

   cin>>noOfShift;

   cout<<" Number of transactions: ";

   cin>>noOfTransaction;

   cout<<"Transaction dollar value:";

   cin>>transactionDollarValue;

   productivityScore = (transactionDollarValue/noOfTransaction)/noOfShift;

   

   if (productivityScore <= 30)

   {

       bonus =50;

       cout<<"Employee’s first name: "<<firstName<<" "<<lastName;

       cout<<endl;

       cout<<"Employee Bonuse: $"<<bonus;

       cout<<endl;

   }

   

   else if (productivityScore >= 79 && productivityScore <=199)

   

   {

       bonus =100;

       cout<<"Employee’s first name: "<<firstName<<" "<<lastName;

       cout<<"Employee Bonuse: $"<<bonus;

   }

   

   else if (productivityScore >= 200)

   

   {

       bonus =200;

       cout<<"Employee’s first name: "<<firstName<<" "<<lastName;

       cout<<"Employee Bonuse: $"<<bonus;

   }

   

   return 0;

}

               

       

6 0
3 years ago
Dr. Wisteria is a prominent chiropractor in the Chicago area. She wants to provide a forum for her patients to discuss their hea
Svet_ta [14]

The best-suited telecommunications tool for Dr. Wisteria is a blog.

a blog

<u>Explanation:</u>

A blog can be defined as an informational website and more a platform for exchanging views and ideas about a particular topic.

There are various blogging platforms available. Dr. Wisteria should start writing blogs about health issues and in this way, she would be able to interact with all the people accessing the blog. People can also post their queries about their health issues and Dr. Wisteria can always reply to them.

This would also create a lot of awareness about any particular health issue being discussed as it is not necessary that only those people who want to post something will access the blog post, it can always be accessed by anyone.

5 0
3 years ago
Read 2 more answers
10.A chlorine ion (Cl-) would most likely bond with _____.<br><br> A.Cl-<br> B.Mg<br> C.K+<br> D.O
andrezito [222]
B. Mg
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6 0
3 years ago
github Portfolio Balances An investor opens a new account and wants to invest in a number of assets. Each asset begins with a ba
OLEGan [10]

The following code will be used to determine the maximum amount invested

<u>Explanation:</u>

long maxValue(int n, int rounds_rows, int rounds_columns, int into rounds)

{

   // Define the variable to store

   // the maximum amount invested.

   long max = 0;

   

   // Define an array of size n,

   // to store the n investments.

   long *investments = (long*)malloc(sizeof(long)*n);

   int i=0;  

   // Initially set all

   // the investments to 0.

   for(i=0;i<n;i++)

   {

       investments[i] = 0;

   }

   i=0;

   // Run the loop to

   // perform the rounds.

   while(i<rounds_rows)

   {

       // Get the left value

       // of the current round.

       int left = rounds[i][0];

       

       // Get the right value

       // of the current round.

       int right = rounds[i][1];

       // Get the contribution

       // for the current round.

       int contribution = rounds[i][2];

       // Since the user uses 1-based

       // indexing, subtract 1 from left

       // and right as the program uses

       // 0-based indexing. That is, the

       // investments in the array start

       // from 0 and not 1.

       right = right - 1;

       int j=0;

       // Run the loop to add the

       // contribution to all the investments

       // between left and right, both inclusive.

       for(j=left; j<=right; j++)

       {

           investments[j] += contribution;

       }

       i++;

   }

   // Traverse the investments array

   // to find the maximum element.

   max = investments[0];

   for(i=1; i<n;i++)

   {

       if(investments[i]>max)

       {

           max = investments[i];

       }

   }

   // Return the

   // maximum investment.

   return max;  

}

6 0
3 years ago
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