Answer:
void print2(int row) {
for (int i = 0; i < row; i++) {
char ch = 'a';
char print = ch;
for (int j = 0; j <= i; j++) {
cout << print++;
}
cout << endl;
}
}
int count_digits(int num) {
int count = 0;
int temp = num;
while (temp != 0) {
temp = temp / 10;
count++;
}
return (num % count);
}
Explanation:
If all accounts you have have the same password, then if someone gets the password to one account, then that person has access to all your accounts.
Answer:
class Example:
def __init__(self, val):
self.val = val
def __gt__(self, other):
return self.val > other.val
def __sub__(self,other):
return abs(len(self.val) - len(other.val))
def main():
obj1 = Example('this is a string')
obj2 = Example('this is another one')
print(obj1 > obj2)
print(obj1 - obj2)
main()
\color{red}\underline{Output:}
Yes, the longer the Key the harder the encryption i believe
