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FrozenT [24]
3 years ago
12

Which of the following expressions is equivalent to 6m - 10?

Mathematics
1 answer:
anastassius [24]3 years ago
3 0
<span>6m - 10

Test each answer to find out which one's correct.
</span><span>2(3m + 5)
6m + 10

</span><span>-2(5 - 3m)
-10 + 6m
6m - 10

</span><span>2(3m - 10)
</span>6m - 20

The correct answer is <span>-2(5 - 3m).
</span>
You might be interested in
Zoom in to see more clear :)
algol13

Answer:

1) x=30 degrees

2)y=20 degrees

1) 3x+2x+1x= 6x (a triangle is normally 180 degrees) 180 divide 6=30 (this is because 6 Xs make up the triangle)

2) 2y+5y+5+y+15= 8y+20, (since a triangle has 180 degrees) 8y+20=180 (-20 from both sides) 8y=160, 160 divide 8=20

(I hope this makes sense)

5 0
3 years ago
Determine whether the function shown in the graph is even or odd.
olganol [36]

Answer:

even

Step-by-step explanation:

An even function is symmetrical about the y- axis.

The graph of the function  given is symmetrical about the t- axis and is therefore even.

4 0
2 years ago
Read 2 more answers
Why can’t -3/4 be a integer
alexandr1967 [171]

Answer:

It can't be an integer because it's not a whole number. Integers are whole numbers, either positive or negative.

7 0
3 years ago
HELP. How long is the minor axis for the ellipse shown below?
kifflom [539]

Given:

The equation of ellipse is

\dfrac{(x+4)^2}{25}+\dfrac{(y-1)^2}{16}=1

To find:

The length of the minor axis.

Solution:

The standard form of an ellipse is

\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1      ...(i)

where, (h,k) is center, if a>b, then 2a is length of major axis and 2b is length of minor axis.

We have,

\dfrac{(x+4)^2}{25}+\dfrac{(y-1)^2}{16}=1      ...(ii)

On comparing (i) and (ii), we get

b^2=16

Taking square root on both sides.

b=\pm 4

Consider only positive value of b because length cannot be negative.

b=4

Now,

Length of minor axis = 2b

                                  = 2(4)

                                  = 8

So, the length of minor axis is 8 units.

Therefore, the correct option is B.

8 0
2 years ago
First I will build the envelope. For this, I am using a rectangular piece of material 28m long and 12m wide. Out of this materia
RUDIKE [14]

Answer:

3.728 cm²

90

Step-by-step explanation:

To built the envelope I am using a rectangular piece of material 28 m long and 12 m wide.  

Out of this material, I have to cut patches that are 1/12 the length and 2/15 the width of the whole material.

So, the length of the patches is 28 \times \frac{1}{12} = 2.33 m and the width of the patches is 12 \times \frac{2}{15} = 1.6 m.

Therefore, the area of the patches is (1.6 × 2.33) = 3.728 m² each. (Answer)

Now, the area of the rectangular piece of material is (28 × 12) = 336 m²

Hence, \frac{336}{3.728} = 90.37 ≈ 90 such patches can be made out of the whole material. (Answer)

3 0
2 years ago
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