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Anit [1.1K]
3 years ago
6

T=s+r solve in terms of r

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

r= t-s

Step-by-step explanation:

t= s+r

t-s =r

.•. r= t-s

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A card is drawn from a​ well-shuffled deck of 52 cards. Find the probability of drawing a diamond or a spade.
AveGali [126]

Answer:

2/13

Step-by-step explanation:

For a deck of card

Total cards = 52

Total spade = 4

Total diamond = 4

pr(drawing a spade) = number of spade/total cards

pr(drawing a spade) = 4/52 = 1/13

pr(drawing a diamond)  = 4/52 = 1/13

Pr(diamond or a spade) = 1/13 + 1/13 = 2/13

8 0
3 years ago
13.6% complete This is a Single Choice Question; skip ahead to question content A B C D E Confirm Difficulty Level: Moderate Som
Veronika [31]

Answer

about 4 hours and 20 minutes

Step-by-step explanation:

200 divided by 60 is 3.33 or 3 hours and 20 minutes, plus the extra hour

8 0
3 years ago
In 1967, New Zealander Burt Munro set the world record for an Indian motorcycle, on the Bonneville Salt Flats in Utah, with a ma
bagirrra123 [75]

Answer:49 sec

Step-by-step explanation:

Given

Maximum speed to reach is 183.58 mi/h

Length of course is 5 mi

acceleration rate is defined by 60mi/h in 4 sec

therefore acceleration(a)=\frac{v-u}{t}

a=\frac{60\times 60\times 60}{4}

a=54\times 10^3 mi/h^2

To reach a speed of 183.58mi/h with an acceleration of 54\times 10^3 mi/h^2

Using equation of motion

v=u+at

183.58=0+(54\times 10^3)t

t=\frac{183.58}{54\times 10^3}

t=0.00339 hours

t=12.23 s reach maximum speed

To complete course it takes

s=ut+\frac{1}{2}at^2

5=0+\frac{1}{2}\times 54\times 10^3 \times t^2

t=0.01360 hour

or t=48.98\approx 49 s

7 0
3 years ago
Step 3a: Calculating the average rate
Alex73 [517]

9514 1404 393

Answer:

  a) average rate = (total distance)/(total time)

  b) Rave = 2·R1·R2/(R1 +R2)

  c) cheetah's average rate ≈ 50.91 mph

Step-by-step explanation:

a) Let AB represent the distance from A to B. Let t1 and t2 represent the travel times (in hours) on leg1 and leg2 of the trip, respectively. Then the distances traveled are...

  First leg distance: AB = 70·t1   ⇒   t1 = AB/70

  Second leg distance: AB = 40·t2   ⇒   t2 = AB/40

The average rate is the ratio of total distance to total time:

  average rate = (AB +AB)/(t1 +t2)

  average rate = 2AB/(AB/70 +AB/40) = 2/(1/70 +1/40) = 2(40)(70)/(70+40)

  average rate = 560/11 = 50 10/11 . . . mph

__

No equations are given, so we cannot compare what we wrote with the given equations. In each step of the solution, we have used the rules of algebra and equality.

b) For two rates over the same distance (as above), the average is their harmonic mean:

  average rate = 2r1·r2/(r1+r2)

__

c) The cheetah's average rate was 50 10/11 mph ≈ 50.91 mph.

4 0
3 years ago
Which table shows a linear relationship
drek231 [11]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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