Width: W
Length: L = W + 8
Perimeter = 2W + 2L = 2(W) + 2(W+8) = 184 (ft)
Solving for W: 2W + 2W + 16 = 184 (ft)
4W = 168 ft, and so W = 42 ft.
The length, L, is (42 + 8) ft = 50 ft. (answer)
Its all up to you and how hard you are willing to work to get that may credits in one semester. But you could do it. Hope that helped!
Answer: 460 students
Step-by-step explanation:
Based on the information given in the question, let the total number of students that attend I.S. 59 be represented by x.
Since we've been given the information that 230 signed up for the school picnic which was 50% of all students in the school. Then, the students in the school will be:
= 50% of x = 230
0.5 × x = 230
0.5x = 230
x = 230/0.5
x = 460
Therefore, 460 students attend the school.
Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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