Answer:
∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and lies between AB and KM and BK is the transversal line)
m∠MBK ≅ m∠BKM (Angles opposite to equal side of ΔBMK are equal)
Step-by-step explanation:
Given: BK is an angle bisector of Δ ABC. and line KM intersect BC such that, BM = MK
TO prove: KM ║AB
Now, As given in figure 1,
In Δ ABC, ∠ABK = ∠KBC (∵ BK is angle bisector)
Now in Δ BMK, ∠MBK = ∠BKM (∵ BM = MK and angles opposite to equal sides of a triangle are equal.)
Now ∵ ∠MBK = ∠BKM
and ∠ABK = ∠KBM
∴ ∠BKM= ∠ABK
Therefore AB ║KM (∵ ∠BKM= ∠ABK and BK is the transversal line)
Hence proved.
Answer:
2x-2<1/2
Step-by-step explanation:
when the problem says "two less than" it means we are subtracting 2 from something, in this case, that something is "twice a number" as the problem states. So we would write 2x where x is a variable that represents any number so we have 2x-2<1/2.
Answer:
-11
Step-by-step explanation:
Answer:
Area=76.56 square feet
Step-by-step explanation:
area of a rectangle =base*height = 5ft*8ft= 40 square feet
area of a triangle=(base*height)/2 =(4ft*4ft)/2= 8 square feet
area of a square=base*height =4ft*4ft= 16 square feet
area of a circle =
* r^{2}[/tex]=3.14*
= 12.56 square feet
r = radius
Total area=(40+8+16+12.56)square feet
Total area=76.56square feet
Answer:
5 and 50
Step-by-step explanation:
Constant of proportionality=(10-5)/(2-1)=5
Distance is 5*10=50
