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il63 [147K]
3 years ago
6

In the right △ABC with m∠C=90°, m∠B=75°, and AB = 12 cm. Find the area of △ABC.

Mathematics
1 answer:
azamat3 years ago
7 0

Given that ABC is a right angle triangle with m∠C=90°,  m∠B=75° and AB=12cm.

Area of triangle =  

                         =  

So we need to find BC,AC now.

To find them let us take sinB and cosB.

SinB =  

BC = 12* cos B = 12* cos 75

So, area =  

            = 72*sin(75)*cos(75)

            = 36*(2sin(75)cos(75))

            = 36*sin(150) =  18

Hence area of triangle is 18

Hope this helps tbh sorry I was a little late btw (:

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Step-by-step explanation:

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= Solution ,

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Now ,

area ( a ) = l × b

or, ( 30x²y + 20xy ) = L × 10xy cm

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\boxed{\sf{l = (3x+2)cm}}

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= \boxed{\sf {2xy}}

hope it helped !!!!

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