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il63 [147K]
3 years ago
6

In the right △ABC with m∠C=90°, m∠B=75°, and AB = 12 cm. Find the area of △ABC.

Mathematics
1 answer:
azamat3 years ago
7 0

Given that ABC is a right angle triangle with m∠C=90°,  m∠B=75° and AB=12cm.

Area of triangle =  

                         =  

So we need to find BC,AC now.

To find them let us take sinB and cosB.

SinB =  

BC = 12* cos B = 12* cos 75

So, area =  

            = 72*sin(75)*cos(75)

            = 36*(2sin(75)cos(75))

            = 36*sin(150) =  18

Hence area of triangle is 18

Hope this helps tbh sorry I was a little late btw (:

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6 0
3 years ago
Identify the quotient in the form a + bi. HELP ASAP PLEASE!!
Step2247 [10]

Solving the expression \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression: \frac{4-5i}{2+3i}

Multiplying and dividing by 2-3i

=\frac{4-5i}{2+3i}*\frac{2-3i}{2-3i}\\=\frac{4-5i*2-3i}{2+3i*2-3i}\\=\frac{4(2-3i)-5i(2-3i)}{(2)^2-(3i)^2}\\=\frac{8-12i-10i+15i^2)}{4-9i^2}\\We\,\,know\,\, i^2=-1\\=\frac{8-12i-10i+15(-1)}{4-9(-1)}\\=\frac{8-15-12i-10i}{4+9}\\=\frac{-7-22i}{13}\\=-\frac{7}{13}-\frac{22i}{13}

So, solving the expression \frac{4-5i}{2+3i} we get -\frac{7}{13}-\frac{22i}{13}

So, Option A is correct.

Keywords: Complex numbers

Learn more about Complex numbers at:

  • brainly.com/question/10736268
  • brainly.com/question/4678474

#learnwithBrainly

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