Given that ABC is a right angle triangle with m∠C=90°, m∠B=75° and AB=12cm.
Area of triangle =
=
So we need to find BC,AC now.
To find them let us take sinB and cosB.
SinB =
BC = 12* cos B = 12* cos 75
So, area =
= 72*sin(75)*cos(75)
= 36*(2sin(75)cos(75))
= 36*sin(150) = 18
Hence area of triangle is 18
Hope this helps tbh sorry I was a little late btw (:
Answer:
C and H
Explanation:
All others are not the same shape, they tend to be pointing in different directions.
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