<span>25 - (60% × 25) =
</span><span>25 - 60% × 25 =
</span>(1 - 60%) × 25 =
<span>(100% - 60%) × 25 =
</span><span>40% × 25 =
</span><span>40 ÷ 100 × 25 =
</span><span>40 × 25 ÷ 100 =
</span><span>1,000 ÷ 100 =
</span><span>10;
The answer is 10</span>
Answer:
26
Step-by-step explanation:
[(7+3)5-4]/2+3
-To solve this equation you have to use PEMDAS
P- Parentheses
E- Exponents
M- Multiplication
D- Division
A- Addition
S- Subtraction-
- With MD and AS you work left to right of the equation since they are in the same spot. (PE[MD][AS])
Step 1) [(10)5-4]/2+3
- First you do "P," parentheses, so you add 7+3=10
Step 2) [50-4]/2+3
- Next you do "M," multiplication, and multiply 10x5=50
Step 3) [46]/2+3
- Then you do "S," subtraction, and subtract 50-4=46
(FYI: Steps 1-3 were still in the parentheses. We had to start with the parentheses in the parentheses, work PEMDAS, and now we are out of the parentheses and have to work PEMDAS on the rest of the problem.)
Step 4) 23+3
- Now we do "D," division, and divide 46/2=23
Step 5) 23+3=6
- Finally we do "A," addition, and add 23+3=26 so the answer is 26
(FYI: "/" means division)
Let's call n the number of days Marika's been training for the race, and 
the distance she runs on the nth day in meters. After the first day, when n = 1, she runs 100 meters, so
On the second day, she runs an additional 4 meters, on the third day, another 4, and so on. Here's what that looks like mathematically:
It would be easier to write this continued addition as multiplication, in which case those same equations would look like
Notice that, in every case, the number 4 is being multiplied by is 1 less than n. We could even write for our first term that 
. In general, we can say that
Which is expressed by option B.
(Bonus: What piece of information from this question did we not need to use here?)
Answer:
D
Step-by-step explanation:
The average rate of change of f(x) in the closed interval [ a, b ] is
Here { a, b ] = [ - 1, 2 ], thus
f(b) = 4 ← from (2, 4 )
f(a) = 
← from (- 1, ) , thus
average rate of change = 
= 
= 
→ D
