We have two points, (3,0) and (0,-3). So we can find the slope of the line:
m=(y2-y1)/(x2-x1)
m=(-3-0)/(0-3)
m=-3/-3
m=1 so far for the line y=mx+b we have:
y=x+b, b is the y intercept which we were told is -3 so
y=x-3
The above is called the slope-intercept form of a line, y=mx+b, the standard form of a line is ax+by=c, so we need to get both variables on one side of the equation..
y=x-3 subtract x from both sides
-x+y=-3
While the above may be acceptable to some, technically the coefficient of x should be expressed as a positive value, so we should divide the above "solution" by -1 to get:
x-y=3
Answer:
a
Step-by-step explanation:
Jeff has -15$ his gf faith gives him 7.
For the first option, since when x is going down (to the left) the function is going up, it's not approaching 0. For the second option, since when x is going up (to the right) it's going up, it's not approaching negative infinity (negative infinity is all the way down). For the third one, since when x is going down the y values are climbing, we can assume that the function's values go to positive infinity. For the last one, since when x=0 y=0, when x=0 the function does not go to infinity
