All categories

3 years ago

Six cakes cost £2.40 how much do ten cakes cost

1 answer:

4 0

There are a few ways to find out the correct answer. One of them is to divide 2.40 by 6 to get a price of one cake and then multiply it by 10:

2.40 ÷ 6 = 0.40
0.40 * 10 = 4.00

Answer: Ten cakes would cost 4 pounds.

You might be interested in

Find the 18th term in the following arithmetic sequence. 7,4,1,-2,-5...

Nataliya [291]

The pattern is n-3, so we will start from the beginning, from 1.
7, 4, 1, -2, -5, -8, -11, -14, -17, -20, -23, -26, -29, -32, -35, -38, -41, -44.
-44 is the 18th term in the sequence.

8 0

3 years ago

Read 2 more answers

Solve 2x^2 + x - 4 = 0 <br> X2 +

damaskus [11]

Answer:

$\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }$

Step-by-step explanation:

Hello, please find below my work.

$2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0$

$\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0

3 years ago

What is the value of x? Enter your answer in the box.

Radda [10]

Answer:

x = 8

y = 6

Step-by-step explanation:

First and foremost, it's an equilateral triangle, therefore all sides and angles are equal.

Knowing that the sum of angle in a triangle is 180°, therefore each angle is 60°.

Then equating (7x+4)° to 60, we have that,

7x+4=60

7x=60-4

7x=56

x=56÷7

x=8.

5 0

2 years ago

Here are the scores of 16 students on an algebra test. 63, 64, 68, 71, 72, 73, 74, 75, 75, 85, 86, 87, 90, 91, 92, 93 Notice tha

Studentka2010 [4]

here you go, I think this is right

3 0

3 years ago

If j(x)=3x+1, find x if j(x)=-11

vladimir1956 [14]

Answer:

x = -4

Step-by-step explanation:

Step 1: Define

j(x) = 3x + 1

j(x) = -11

Step 2: Substitute and solve for <em>x</em>

-11 = 3x + 1

-12 = 3x

x = -4

6 0

3 years ago