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gayaneshka [121]
2 years ago
13

( x + 30 ) ( x + 40 ) solve for x

Mathematics
2 answers:
PolarNik [594]2 years ago
7 0

Answer:

Step-by-step explanation:

(x+30)(x+40)

X(x+40) +30(X+40)

X²+40x+30x+1200

X²+70x+1200

by applaying quadrtic fromula we get

a=1, b=70, c=1200

(-b ± √(b2 − 4ac))/(2a)

put the values

(-70±√(70)²-4(1)(1200)/2(1)

(-70±√4900-4800)/2

(-70±√100)/2

(-70±10)/2

either                                       or

-70+10/2                                    -70-10/2

-60/2                                             -80/2

-30                                                   -40

so x={-30,-40}

vazorg [7]2 years ago
5 0

Answer:

X^2 + 70x + 12000

Step-by-step explanation:

Is that what you wanted? I got that by using the distributive method.  

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well, the sequence goes, 1100, to 1135, to 1170.... notice, is simply adding 35 to get the next term, so the common difference is 35, and the first term is 1100 of course.


\bf n^{th}\textit{ term of an arithmetic sequence}
\\\\
a_n=a_1+(n-1)d\qquad
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\[-0.5em]
\hrulefill\\
a_1=1100\\
d=35\\
a_n=3725
\end{cases}
\\\\\\
3725=1100+(n-1)35\implies 3725=1100+35n-35
\\\\\\
3725=1065+35n\implies 2660=35n\implies \cfrac{2660}{35}=n\implies 76=n

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