Answer:
Mailing preparation takes 38.29 min max time to prepare the mails.
Step-by-step explanation:
Given:
Mean:35 min
standard deviation:2 min
and 95% confidence interval.
To Find:
In normal distribution mailing preparation time taken less than.
i.eP(t<x)=?
Solution:
Here t -time and x -required time
mean time 35 min
5 % will not have true mean value . with 95 % confidence.
Question is asked as ,preparation takes less than time means what is max time that preparation will take to prepare mails.
No mail take more time than that time .
by Z-score or by confidence interval is
Z=(X-mean)/standard deviation.
Z=1.96 at 95 % confidence interval.
1.96=(X-35)/2
3.92=(x-35)
X=38.29 min
or
Confidence interval =35±Z*standard deviation
=35±1.96*2
=35±3.92
=38.29 or 31.71 min
But we require the max time i.e 38.29 min
And by observation we can also conclude the max time from options as 38.29 min.
The measure of ∠K is 49 degrees 22 minutes 51 seconds.
<u>Step-by-step explanation:</u>
Given that ∠J and ∠K are complementary.
∠J = 41°38'9".
∠K = ?
When a sum of two angles result is 90°, then it is called as complementary angles.
Since ∠J and ∠K are complementary, then their sum is 90°.
∠J +∠K=90°.
∠K= 90° - ∠J.
=90°60'60" - 41°38'9".
=49°22'51".
∠K= 49 degrees 22 minutes 51 seconds.
Answer:
Its B
Step-by-step explanation:
If you look at how the chart is flowing, the y values are 2 times the x value.
for example,
1x2=2
2x2=4
3x2=6
and
4x2=8
Therefore, the equation is linear and y=2x
Answer:
C
Step-by-step explanation:
Not integer, irrational
