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serg [7]
3 years ago
14

Which system of linear equations appears to have a solution of (–1, 4)? On a coordinate plane, 2 lines intersect at (1, negative

4). On a coordinate plane, 2 lines intersect at (1, 4). On a coordinate plane, 2 lines intersect at (negative 1, negative 4). On a coordinate plane, 2 lines intersect at (negative 1, 4).
Mathematics
2 answers:
kozerog [31]3 years ago
7 0

Answer:

On a coordinate plane, 2 lines intersect at (3, 0).

Step-by-step explanation:

madam [21]3 years ago
6 0

Answer:

On  coordinate plane, 2 lines intersect at (negative 1, 4)

Step-by-step explanation:

negative 1 = -1, 4 = 4

therefore this means that this coordinate is also (-1, 4)

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2 years ago
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Eloise started to solve a radical equation in this way: Square root of negative 2x plus 1 − 3 = x Square root of negative 2x plu
andreyandreev [35.5K]
Here I copy the steps and indicate where the error is.

Square root of negative 2x plus 1 − 3 = x=> <span>this is the starting equation
</span>

√[ - 2x + 1] - 3 = x

Square root of negative 2x plus 1 − 3 + 3 = x + 3 in this step she added 3 to each side, which is fine

<span> Square root of negative 2x plus 1 = x + 3 <span>she made the addtions => fine</span></span>

Square root of negative 2x plus 1 − 1 = x + 3 – 1 due to <span>plus 1 in inside the square root, this step will not help</span>

<span> Square root of negative 2 x = x + 2 <span>wrong! she cannot simplify - 1 that is out of the square root with +1 that is inside the square root
</span></span>


<span>Then, from here on all is wrong, but she made other additional mistakes.</span>

(Square root of negative 2 x)2 = (x − 4)2 −2x <span> the right side should be (x+2)^2 which is x^2 + 4x +4 not (x-4)^2 - 2x</span>

Later she made a mistake changing the sign of -8x to +8x


Those are the mistakes. Finally, the global error is that she should verify whether the found values satisfied the original equation.

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