Answer:
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
And the 90% confidence interval would be given (0.131;0.169).
Step-by-step explanation:
We have the following info given:
represent the sampel size slected
number of students who read above the eighth grade level
The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:
The confidence interval for the proportion would be given by this formula
For the 90% confidence interval the significance is 
and 
, with that value we can find the quantile required for the interval in the normal standard distribution and we got.
And replacing into the confidence interval formula we got:
And the 90% confidence interval would be given (0.131;0.169).
Answer:
You wrote the numbers from 1 to 9: 9 digits.
You wrote the numbers from 10 to 99: 90*2 = 180 digits.
You have written 189 digits.
Then you wrote another 1994 - 189 = 1805
All the numbers from 100 to 999 have 3 digits
So you wrote 1805/3 = 601 2/3
This means 601 full numbers and 2 digits from the 602. number.
So 100 + 601 - 1 = 700 was the last number you wrote.
Do you agree?
Ok, so if you want to convert 7/8 into a decimal, you just simply divide 7 into 8. Well that should be 0.875 because 7 ÷ 8 = 0.875 Hope that helped!!! :)
If r(x)= 11x, and c(x)=6x +20, then just put that into the equation.
So instead of p(x) = r(x) - c(x)
I would be p(x) = 11x - 6x + 20
Now solve.
p(x) = 5x + 20 is your final answer, so A.
900. It estimates bc one is like 288 and one is like 624 or sum.
