Answer:
3sq units
Step-by-step explanation:
bxh = 2x3=6
6/2=3
Company A: 120 + 0.50x
Company B: 60 + 0.60x
Company A = Company B (solve for x)
(Here, x = miles)
120 + 0.50x = 60 + 0.60x
120 - 60 = 0.60x - 0.50x
60 = 0.10x
600 = x
Answer:
1/216
Step-by-step explanation:
I am pretty sure this is correct
you have to make the whole number 6 into a fraction 6/1
now it is 1/6 divided by 6/1 but you need to do KCF keep change flip
so now it is 1/6 times 1/6 and you get 1/36
then turn 6 into a fraction again
then KCF
Now it is 1/36 times 1/6 and you get 1/216
Complete question :
Birth Month Frequency
January-March 67
April-June 56
July-September 30
October-December 37
Answer:
Yes, There is significant evidence to conclude that hockey players' birthdates are not uniformly distributed throughout the year.
Step-by-step explanation:
Observed value, O
Mean value, E
The test statistic :
χ² = (O - E)² / E
E = Σx / n = (67+56+30+37)/4 = 47.5
χ² = ((67-47.5)^2 /47.5) + ((56-47.5)^2 /47.5) + ((30-47.5)^2/47.5) + ((37-47.5)^2/47.5) = 18.295
Degree of freedom = (Number of categories - 1) = 4 - 1 = 3
Using the Pvalue from Chisquare calculator :
χ² (18.295 ; df = 3) = 0.00038
Since the obtained Pvalue is so small ;
P < α ; We reject H0 and conclude that there is significant evidence to suggest that hockey players' birthdates are not uniformly distributed throughout the year.
