Find the exterior angle of a 15-gon

1 answer:

3 0

$\bf \textit{sum of all exterior angles in a polygon}\\\\ n\theta =360~~ \begin{cases} n=\textit{number of}\\ \qquad sides\\ \theta =angle~in\\ \qquad degrees\\[-0.5em] \hrulefill\\ n=15 \end{cases}\implies 15\theta =360\implies \theta =\cfrac{360}{15}\implies n=24$

You might be interested in

A test consists of 100 multiple choice questions, each with five possible answers, only one of which is correct. Find the mean a

TEA [102]

Answer: Mean = 20 and standard deviation = 4

Step-by-step explanation:

Let x represents the success of getting the correct answer.

Here, the total number of trials(n) = 100

The probability of getting the correct answer, p = 1/5

Thus, the mean of the number of correct answer,

$\mu_x= np$

$\mu_x= 100\times 1/5$

$\mu_x= 20$

Now, the standard deviation, $\sigma_x= \sqrt{n\times p\times (1-p)}$

$\sigma_x= \sqrt{100\times 1/5\times 4/5}$

$\sigma_x= \sqrt{16}$

$\sigma_x= 4$

Thus, First option is correct.

6 0

3 years ago

two sides of a parallelogram meet at an angle of 50 degrees. If the length of one side is 3 meters and the length of the other s

Anon25 [30]

Answer:

The longer diagonal has a length of 7.3 meters.

The angles are 31.65° and 18.35°

Step-by-step explanation:

If one angle of the parallelogram is 50°, another angle is also 50° and the other two angles are the supplement of this angle. so the other three angles are:

50°, 130° and 130°.

The longer diagonal will be the one opposite to the bigger angle (130°), and this diagonal divides the parallelogram in two triangles.

Using the law of cosines in one of these two triangles, we have:

$diagonal^2 = a^2 + b^2 - 2ab*cos(130\°)$