To solve:
T/6-14=-20
+14 +14 ISOLATE T/6: inverse operations on -14. (Add)
-----------------
T/6= 6
*6 *6 ISOLATE T: Inverse operations on 6. (Multiply)
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T=36
The mathematical terms that cannot be defined for all
cases in a system of geometry are the parallel lines and midpoint of a line
segment. A line is an infinite series of points in a row and it does not occupy
any space. They are also called one dimensional since the direction is in one
dimension. A point has a location but no specific size. It can describe a
location but you can never determine its actual size. Imagine the point at the
end of the previous sentence. And then imagine it getting smaller and smaller
until it disappears. We can only use a dot to represent the point.
The answer is 566m because 147 plus 147 and 136 plus 136 equals 566
G(f(2)) means work out whatever f(2) is then plug this into g(x).
So f(2) is 3 because we just find the x-value 2 in the left hand column and read across. This is 3.
So then we find g(3) by finding the x-value 3 in the left hand column and read across. This is 10.
So g(f(2)) = 10
Answer:
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
Step-by-step explanation:
First we have to calculate the area, for this we must multiply the length by the width
a = area
l = long = 55yd
w = width = 35yd
a = l * w
a = 55yd * 35yd
a = 1925yd²
to calculate the volume we have to multiply the area by the height
asks us for the volume for half the height so we have to divide the height by 2
a = area = 1925yd²
h = height = 5yd/2 = 2.5yd
v = volume
v = a * h
v = 1925yd² * 2.5yd
v = 4812.5yd³
The area of the warehouse floor is 1925yd²
The volume of the boxes is 4812.5yd³
