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maxonik [38]
3 years ago
15

3y+4=11y PLEASE STEP BY STEP: SHOW WORK PLEASE AND THANK YOU !!

Mathematics
2 answers:
Snezhnost [94]3 years ago
7 0
3y+4=11y
4=8y
0.5=y

y=0.5
bija089 [108]3 years ago
4 0
3y + 4 = 11y
(take away 3y from both sides)
4         = 8y
(divide by 8 on both sides)
0.5      = y

y = 0.5

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An old bone contains 80% of its original carbon-14. Use the half-life model to find the age of the bone. Find an equation equiva
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Answer:

An old bone contains 80% of its original carbon-14 in 1844.6479 years

Step-by-step explanation:

We know that

half life time of C-14 is 5730 years

so, h=5730

now, we can use formula

P(t)=P_0(\frac{1}{2})^{\frac{t}{h} }

we can plug back h

and we get

P(t)=P_0(\frac{1}{2})^{\frac{t}{5730} }

An old bone contains 80% of its original carbon-14

so,

P(t)=0.80Po

we can plug it and then we solve for t

0.80P_0=P_0(\frac{1}{2})^{\frac{t}{5730} }

0.80=(\frac{1}{2})^{\frac{t}{5730} }

\ln \left(0.8\right)=\ln \left(\left(\frac{1}{2}\right)^{\frac{t}{5730}}\right)

t=-\frac{5730\ln \left(0.8\right)}{\ln \left(2\right)}

t=1844.6479

So,

An old bone contains 80% of its original carbon-14 in 1844.6479 years


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