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romanna [79]
3 years ago
15

a skate shop rents roller skates as shown in the table below which graph and function model this situation,where c is the cost,i

n dollars,of renting skates,and t is the number of hours in a single day that the skates are rented

Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0

Answer:

<u>A) Function</u>

c(t)=\begin{cases} 5\text{ if }0

<u>B) Graph: see the graph attached</u>

Explnation:

The question is incomplete. The missing table is:

Roller Skate Rentals

        Time                         Cost

Up to 60 minutes               $5

Up to 2 hours                    $10

Up to 5 hours                    $20

Daily                                   $25

<h2>Solution</h2>

<u>1) Function</u>

The situation is represented by a piecewise function;

<u>Up to 60 minutes is up to 1 hour.</u>

Of course for 0 minutes, the cost is zero.

If the times is greater than zero and less than or equal to 1 hour the cost is $5. That is modeled by:

         5\text{   }if\text{    }0

<u>Up to 2 hours</u>

If the time is greater than 1 hour and less than or equal to 2 hours, the cost is $10. That is modeled by:

         10\text{   }if\text{    }1

<u>Up to 5 hours</u>

If the time is greater than 2 hours and less than or equal to 5 hour, the cost is $20. That is modeled by:

         20\text{   }if\text{    }2

<u>Up to 1 day</u>

If the time is greater than 5 hours and less than or equal to 24 hour, the cost is $25. That is modeled by:

        25\text{   }if\text{    }5

Now joint the four pieces:

c(t)=\begin{cases} 5\text{ if }0

<u>2) Graph</u>

The graph of this piecewise function has 4 different horizontal line segments.

The first segment in the interval 0 < t  ≤ 1 is at c(t) = 5, which means that:

  • the left end of the segment must show an open circle, and
  • the right end of the segment must show a solid circle.

The second segment , in the interval 1 < t  ≤ 2, at c(t) = 10:

  • the left end of the segment is an open circle
  • the right end of the segment is a solid circle

The third segment in the interval 2 < t ≤ 5, at c(t) = 20.

  • the left end of the segment shows an open circle
  • the right end of the segment shows a solid circle

The fourth segment in the interval 5 < t ≤ 24, at c(t) = 25.

  • the left end of the line shows an open circle
  • the right ent of the line shows a solid circle

See the graph attached

12345 [234]3 years ago
5 0

Answer:

The other guy is correct so I'll just make it simpler. The correct answer is D

Step-by-step explanation:

I got it right on the quiz

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finlep [7]

Answer:

The answer is "0.90>p>0.75."

Step-by-step explanation:

\text{Cinnabar vestigial} \ \ \ \ \ \ \ \ \ \ \ 384 \ \ \ \ \ \ \ \ \ \ \ 390 \ \ \ \ \ \ \ \ \ \ \  -6 36 \ \ \ \ \ \ \ \ \ \ \  0.092308\\\\

roof \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  408 \ \ \ \ \ \ \ \ \ \ \  390  \ \ \ \ \ \ \ \ \ \ \  18 \ \ \ \ \ \ \ \ \ \ \  324  \ \ \ \ \ \ \ \ \ \ \ 0.830769\\\\\text{Cinnabar vestigial roof} \ \ \ \ \ \ \ \ \ \ \ \ \ 63 \ \ \ \ \ \ \ \ \ \ \ \ \  70\ \ \ \ \ \ \ \ \ \ \ \ -7 \ \ \ \ \ \ \ \ \ \ \  49 \ \ \ \ \ \ \ \ \ \ \  0.7\\\\\text{wild type} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 72  \ \ \ \ \ \ \ \ \ \ \  70  \ \ \ \ \ \ \ \ \ \ \ 2  \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \  0.057143\\\\

vestigial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 32 \ \ \  \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ -3 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.257143\\\\

\text{Cinnabar roof} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 34\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  -1 \ \ \ \ \ \ \ \ \ \  \ \ \ \ \ \ \ \  1  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.028571\\\\\text{roof vestigial}  \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  5 \ \ \ \ \ \ \ \ \ \ \ \ \ \ -1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.2\\\\

\text{cinnabar}  \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  3 \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \  5 \ \ \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \  -2\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  0.8 \\\\

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Eight phenotypes were present.  

Df is provided also by a number of phenotypes -1 The degree of freedom

\to df = 8-1= 7

For p-value 0,9, Chi-square is 2.83;

The p-value of 0.75 is 4.5. Chi-square

Chi-sqaure value is observed at 2.965.

That means 0.90>p-value>0.75.

7 0
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