How do i get the answer to this? 2g + 4g + 5g
2 answers:
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Answer: 0.0208
Step-by-step explanation:
Given: The length of time to find a parking spot on the UW campus is normally distributed with a mean of 4.75 minutes and a standard deviation of 1.35 minutes.
Let x = time taken to find parking spot
The probability that a randomly selected driver takes less than 2 minutes to find a parking spot on the UW campus will be :
Hence, the probability than a randomly selected driver takes less than 2 minutes to find a parking spot on the UW campus.= 0.0208