Answer:
filtration
Explanation:
1.put the mixture in a beaker
2.add water to the beaker and stir to dissolve salt
3.filter using a filter paper to have sand as the residue
4.Evaporate the water to remain with salt crystals
This is due to the hydroxyl group in the alcohol which is able to form hydrogen bonds with water molecules.
Answer:
Acids dissolve in water to produce a solution that tastes bitter.
Acids dissolve in water to produce a solution that reacts with metals to produce H2 gas.
Acids dissolve in water to produce a solution that cannot conduct electricity.
Acids dissolve in water to produce a solution that is slippery.
Answer:
The correct order of increasing reactivity toward nucleophilic acyl substitution is E < D < C < A < F < B.
Explanation:
The stability of the leaving group best determines the manner of reactivity of carboxylates to nucleophilic substitution after the substitution of the nucleophile to the leaving group. The leaving group should, therefore, be protonated with hydrogen ion in the solution to form a stable molecule. From the given list: The leaving group for A, Ethyl thioacetate will be ethanethiol. For B, Acetyl chloride will be Hydrochloric acid. For C, Sodium acetate will be Sodium Hydroxide. For D, Ethyl acetate will be Ethanol. For E, Acetamide will be Ammonia, and for F, Acetic anhydride will be Ethanoic acid. The reactivity of the substitution reaction is dependent on the stability of these leaving groups. The stability of these leaving groups depends on their pKa, and the more the pKa, the lesser the acidity of the leaving group, and the lower the reactivity. Therefore, considering their pKa: A is 8.5, B is -7, C is 13.8, D is 15.9, E is 36, and F is 4.8. When we rearrange this pKa in descending order, we have E, D. C, A, F, B. Which is also the increased reactivity of the nucleophilic acyl substitution.
Based on the mass given, the value of P in the N - P - K designation is 32.
<h3>What is percentage mass composition of an element?</h3>
The percentage mass composition of an element is the mass percent ofbthe element in the the total mass of the compound.
Since the fertilizer contains 1.2 g of phosphorus as P2O5.
Molar mass of P2O5 = 142 g
mass percent of P in P2O5 = 2 × 31/142 = 43.6%
mass of P2O5 in 8.6 g fertilizer = 100/43.6 × 1.2 = 2.75 g
Mass percent of P2O5 = 2.75/8.6 × 100% = 32.0%
Therefore, the value of P in the N - P - K designation is 32.
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