The length is 1.36 feet and the breadth is 17.647 feet of the plate, if friction drag is 0.3 lbf.
T = 20°C = 293 K
P = 1 atm = 101.325kP
P = ρRT
ρ = 1.205 kg/m³
Total drag = C∝ * (1/2 .ρ . A . V²)
0.3 lbf = C∝ * 1/2 * 1.205 * 4.645 * (15.24)²
C∝ = 2.05338 * 10 ⁻³
Now,
C∝ = 1.328 / √Re
2.05338 * 10 ⁻³ = 1.328 / √Re
∴ Re = 418267.61
∴ ρ. v. l/μ = 418267.61
1.205 * 15.24 *L/18.207 * 10⁻⁶ = 418267.61
Length = 0.4147 m = 1.36 foot
L * B = 24 ft²
1.36 * B = 24
∴ breadth = 17.647
Hence, Length is 1.36 feet and the breadth is 17.647 foot.
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