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storchak [24]
3 years ago
7

What is variable????​

Chemistry
2 answers:
emmasim [6.3K]3 years ago
7 0

Answer:

<h3>Variable are all the quantities that could change in an experiment.</h3>

Misha Larkins [42]3 years ago
4 0

Answer:

Basically, a variable is any factor that can be controlled, changed, or measured in an experiment. It's anything that can be changed in the experiment.

Explanation:

Scientific experiments have several types of variables. The independent and dependent variables are the ones usually plotted on a chart or graph, but there are other types of variables you may encounter. The presence/absence of the chemical is the independent variable. The health of the (ex:)rat (whether it lives and can reproduce) is the dependent variable.

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The copper(I) ion forms a chloride salt (CuCl) that has Ksp = 1.2 x 10-6. Copper(I) also forms a complex ion with Cl-:Cu+ (aq) +
Mnenie [13.5K]

Answer: (a) The solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b) The solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

Explanation:

(a)  Chemical equation for the given reaction in pure water is as follows.

           CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq)

Initial:                         0            0

Change:                    +x           +x

Equilibm:                   x             x

K_{sp} = 1.2 \times 10^{-6}

And, equilibrium expression is as follows.

          K_{sp} = [Cu^{+}][Cl^{-}]

       1.2 \times 10^{-6} = x \times x

             x = 1.1 \times 10^{-3} M

Hence, the solubility of CuCl in pure water is 1.1 \times 10^{-3} M.

(b)  When NaCl is 0.1 M,

       CuCl(s) \rightarrow Cu^{+}(aq) + Cl^{-}(aq),  K_{sp} = 1.2 \times 10^{-6}

   Cu^{+}(aq) + 2Cl^{-}(aq) \rightleftharpoons CuCl_{2}(aq),  K = 8.7 \times 10^{4}

Net equation: CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

               K' = K_{sp} \times K

                          = 0.1044

So for, CuCl(s) + Cl^{-}(aq) \rightarrow CuCl_{2}(aq)

Initial:                     0.1                 0

Change:                -x                   +x

Equilibm:            0.1 - x                x

Now, the equilibrium expression is as follows.

              K' = \frac{CuCl_{2}}{Cl^{-}}

         0.1044 = \frac{x}{0.1 - x}

              x = 9.5 \times 10^{-3} M

Therefore, the solubility of CuCl in 0.1 M NaCl is 9.5 \times 10^{-3} M.

7 0
3 years ago
A student distills a sample of ink. Devise a simple method to show that the liquid collected is pure water. Include the expected
yulyashka [42]

Answer:

Distillation

Explanation:

Water vaporizes at lower temperature than the ink pigment so if you heat them, the water evaporates, leaving the ink pigment in the flask

4 0
3 years ago
Magnesium carbonate and sulphuric acid react to form​
Mekhanik [1.2K]

Answer:

magnesium sulfate + water + carbon dioxide

Explanation:

4 0
2 years ago
Read 2 more answers
Someone explain what to do here…thanks.
umka21 [38]

Answer:

The answer is 900 000m.

This is because km is 3 times greater than a meter.

6 0
3 years ago
Common coagulants (salts) used in conventional water treatment include the following alum (aluminum sulfate), sodium aluminate,
vladimir2022 [97]

Answer:

True

Explanation:

This is the true statement .

Because There are two types of metal coagulants used : aluminium and iron.

The aluminum coagulants include aluminum sulfate, aluminum chloride and sodium aluminate.

The iron coagulants include ferric sulfate, ferrous sulfate, ferric chloride and ferric chloride sulfate.

7 0
3 years ago
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