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Gnoma [55]
4 years ago
5

Which shape is used to mark equal distances in a construction?

Mathematics
2 answers:
IrinaK [193]4 years ago
6 0
Maybe B. Sorry if this wrong. ><
Margarita [4]4 years ago
6 0

Answer:

it is ray

Step-by-step explanation:


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the correct answer will be b/c

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Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (13, 84) lies
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Answer:

If P = (x,y) then formulas for each trigonometric functions are:

sin x = y/r

cos x = x/r

tan x = y/x

cot x = x/y

sec x = r/x

cosec x = r/y

where r = √(x²+y²).

First find r:

r = √(13²+84²)=√(169+7056)=√7225=85.

Then just substitute:

sin x = 84/85

cos x = 13/85

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f(x)=\frac{1}{\sqrt{x} }\\f'(x)=-\frac{1}{2} x^{-\frac{3}{2}}\\\\f'(4)=-\frac{1}{2} 4^{-\frac{3}{2} }=-\frac{1}{2} \frac{1}{4^\frac{3}{2} } \\=-\frac{1}{2} *\frac{1}{8}=-\frac{1}{16}  \\when x=4\\y=f(x)=\frac{1}{\sqrt{4} } =\frac{1}{2} \\\\eq.~ of ~tangent ~line~is\\y=-\frac{1}{2} -\frac{1}{16} (x-4)

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A transformation T : (x, y) → (x + 3, y + 1). Find the preimage of the point (4, 3) under the given transformation. (7, 4) (1, 2
motikmotik

Answer:

(1, 2)

Step-by-step explanation:

Remember that the final shape and position of a figure after a transformation is called the image, and the original shape and position of the figure is the pre-image.

In our case, our figure is just a point. We know that after the transformation T : (x, y) → (x + 3, y + 1), our image has coordinates (4, 3).

The transformation rule T : (x, y) → (x + 3, y + 1) means that we add 3 to the x-coordinate and add 1 to the y-coordinate of our pre-image. Now to find the pre-image of our point, we just need to reverse those operations; in other words, we will subtract 3 from the x-coordinate and subtract 1 from the y-coordinate.

So, our rule to find the pre-image of the point (4, 3) is:

T : (x, y) → (x - 3, y - 1)

We know that the x-coordinate of our image is 4 and its y-coordinate is 3.

Replacing values:

                (4 - 3, 3 - 1)

                (1, 2)

We can conclude that our pre-image is the point (1, 2).

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