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Verizon [17]
3 years ago
8

What are equivalent fractions to 25/35

Mathematics
1 answer:
Galina-37 [17]3 years ago
4 0
The best way to find fractions that are equal is to find a common factor and divide/multiply them.

So in 25/35 you can easily see that 5 goes into both SO...

25/35 / 5/5 = 5/7

25/35 = 5/7
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Iteru [2.4K]

If im looking at it correct theres no solution

8 0
3 years ago
Kendra is considering two different long-distance phone plans. Phone plan A charges a $100 sign-up fee and 3 cents per minute. P
Fed [463]

Answer:

Part 1) The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2) The number of minutes in a month must be equal to 50 minutes

Step-by-step explanation:

<u><em>The question is</em></u>

Part 1) How many minutes would Kendra have to use in a month in order for the plan A to be preferable? Round your answer to the nearest minute

Part 2) Enter the number of minutes where Kendra will pay the same amount for each long distance phone plan

Part 1)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A to be cheaper than plan B, the following inequality must hold true.

cost of plan A < cost of plan B

substitute

3x+100 < 5x

solve for x

subtract 3x both sides

100< 5x-3x\\100

divide by 2 both sides

50 < x

Rewrite

x> 50\ min

therefore

The number of minutes in a month must be greater than 50 in order for the plan A to be preferable

Part 2)

Let

x ---> the number of minutes

we have

<em>Cost Plan A</em>

3x+100

<em>Cost Plan B</em>

5x

we know that

In order for plan A cost the same than plan B, the following equation must hold true.

cost of plan A = cost of plan B

substitute

3x+100= 5x

solve for x

5x-3x=100\\2x=100\\x=50\ min

therefore

The number of minutes in a month must be equal to 50 minutes

5 0
3 years ago
How far will Charlie travel when driving at 55 mph and traveling for 3 hours?
Igoryamba
55 x 3 = 165 miles per hour
3 0
3 years ago
Read 2 more answers
Gwen, Tristan and Keith like to work out at the gym . They each have an app on their phone that estimates the calories they burn
Anarel [89]

Based on the above scenario, an equation that shows how much Gwen paid. The equation for Gwen is y = 100 + 10x

  • The equation for Tristan is y = 12.5x
  • The equation for Keith is y = 10x.

<h3>What is the  equation  about?</h3>

Since Gwen burns  about 10 cal/min. THen she had used up 100 calories if Tristan and Keith began ar (Y g=100 if  x=0)

Then Y(g)= 10x + 100

Since Tristan is known to burns 125 cal in 10 minutes always, then one can write her own as 12.5 cal every minute.

Therefore Y (t) = 12.5x

Since Keith burns 300 calories in 30 min always, or 10 calories in every minute.

Then Y (k) = 10x

The   general function of y:

y=10x +100 + 12.5x + 10x

y = 32.5x + 100

Therefore, Based on the above scenario, an equation that shows how much Gwen paid. The equation for Gwen is y = 100 + 10x

  • The equation for Tristan is y = 12.5x
  • The equation for Keith is y = 10x.

Learn more about calories from

brainly.com/question/6535979

#SPJ1

7 0
2 years ago
Simplify:<br>a)8×7+4<br>b)17+8×2<br>c)20×3+10<br>d)5+4×15<br>PLZZ help me​
stira [4]

Answer:

a) 60

b) 33

c)70

d)65

Step-by-step explanation:

Use BIDMAS

(brackets, indicies, division, multiplication, addition, subtraction)

7 0
2 years ago
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