The "e" just lets you know that it's scientific notation.
Step-by-step explanation:
In ordee to round the number 7209 to the nearest thousands, we take a look at the digit in the hundreds place (which is 2).
Since 2 < 5, we round the number itself down to the nearest thousands:
7209 => 7000.
Hence our rounded number is 7000.
Answer:
The equivalent will be:
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D%3D%5Cleft%28%5C%3Ax%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%5Cright%29%5Cleft%28y%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%5Cright%29)
Therefore, option 'a' is true.
Step-by-step explanation:
Given the expression
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D)
Let us solve the expression step by step to get the equivalent
as
![\sqrt[7]{x^2}=\left(x^2\right)^{\frac{1}{7}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E2%7D%3D%5Cleft%28x%5E2%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B7%7D%7D)
∵ ![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)
also
![\sqrt[5]{y^3}=\left(y^3\right)^{\frac{1}{5}}](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7By%5E3%7D%3D%5Cleft%28y%5E3%5Cright%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D)
∵
so the expression becomes
∵ 
Thus, the equivalent will be:
Therefore, option 'a' is true.
Answer:
B) y = 3x + 2
Step-by-step explanation:
:)
:)
:)
Hope this helps!
The answer is sequence I (choice A)
The common ratio is r = 1 because we multiply each term by 1 to get the next term. No change happens when we multiply any number by 1. Another way to find the common ratio is to pick any term and divide it by its previous term.
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Choice B is not the answer because (1/5) divided by (1/4) = 0.2/0.25 = 0.8
and because (1/6) divided by (1/5) = 0.833 approximately. We don't get the same value each time. So the common ratio doesn't stay the same.
Choice C is not the answer either since most of the terms are positive but the -4 in slot 3 is not positive. If it was positive, then the common ratio would be 4 and this sequence would be geometric. If the terms alternated between positive and negative, then it would work as well (r would be r = -4)
Choice D has alternating terms of positive and negative, but there's no change in absolute value. There is no growth or decay as this the terms effectively stay the same. So there is no common ratio. This is why we can rule out choice D.
