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Tatiana [17]
3 years ago
9

Which ordered pairs in the form (x, y) are solutions to the equation 3x−4y=21 ?

Mathematics
2 answers:
ioda3 years ago
8 0

Answer:

(-1,-6) , (7,0) and (11,3)

Step-by-step explanation:

3x - 4y = 21

4y = 3x - 21

y = 3/4x - 21/4 , the slope(m) of this line is 3/4

The x and y intercepts are (0,-5.25) and (7,0)

Taking a point (-3,3):

Slope(m) = change in y ÷ change in x

Slope = (3 - 0) ÷ (-3 - 7) = -0.3

Since the slope here is not 3/4 then point (-3,3) is not on the line.

Taking a point (-1,-6)

Slope = (-6 - 0 ) ÷ (-1 - 7) = -6/-8 = 3/4

The point (-1,-6) is on the line.

Taking a point (7,0):

This point is the x - intercept and so its on the line.

Taking a point (11,3):

Slope = (3 - 0) ÷ (11 - 7) = 3/4

Therefore the point (11,3) is on the line.


trasher [3.6K]3 years ago
6 0

Answer:

wut that dude said is correct i verified it

Step-by-step explanation:

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Answer:

7(x - 4) = 14 \\ 7x - 21 = 14 \\ 7x = 14 + 21 \\ 7x = 35 \\  \frac{7x}{7}  =  \frac{35}{7}  \\ x = 5

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Step-by-step explanation:

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2 years ago
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Which of the following could be used to calculate the area of a sector in the circle shown below
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Answer:

Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

Step-by-step explanation:

Given:

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Solution:

We know that

\textrm{Area of Sector}=\pi (Radius)^{2}\times \frac{\theta}{360}

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\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

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Therefore the Last option is correct

\textrm{Area of Sector ACD}=\pi (8\ in)^{2}\times (\frac{42}{360})

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2 years ago
Which statement is true? A. 13/14 > 25/28 B. 21/45 < 4/9 C. 5/6 > 11/12 D. 4/5 < 8/25
nasty-shy [4]

Rewrite the fractions with common denominators and then answer:

A:

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This is True

B) 21/45 < 20/45  False

C) 10/12 > 11/12

False

D) 20/25 < 8/25

False

The true statement is A.

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