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Lesechka [4]
2 years ago
7

Is it A or B or C or D

Mathematics
2 answers:
pantera1 [17]2 years ago
6 0
B and it stands for give me brainless
Elis [28]2 years ago
5 0

Answer:

c

Step-by-step explanation:

because i said so

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A number is as much greater than 21 as it is less than 75 .find the number​
laiz [17]

Answer:

46

Step-by-step explanation:

Let number is x greater than 21 and x less than 71.

Now, according to question,

21+x=71−x

2x=50

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So, required number is 21+x=21+25=46.

Alternatively,

The required number would be the average or mean of 21 and 71.

So, required number =

2

(21+71)

=46.

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A hummingbird eggs’ mass is approximately 0.374 milligram. What is the mass of 4 Hummingbird eggs?
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A membership at a yoga studio costs $35 per month. Write an equation for the cost of the membership, c, that you pay if you keep
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6 0
3 years ago
Consider a uniform distribution from aequals4 to bequals29. ​(a) Find the probability that x lies between 7 and 27. ​(b) Find th
weeeeeb [17]

Answer:

a) 80% probability that x lies between 7 and 27.

b) 28% probability that x lies between 6 and 13.

c) 44% probability that x lies between 9 and 20.

d) 28% probability that x lies between 11 and 18.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value x between c and d, in which d is larger than c, is given by the following formula.

P(c \leq x \leq d) = \frac{d - c}{b - a}

Uniform distribution from a = 4 to b = 29

(a) Find the probability that x lies between 7 and 27.

So c = 7, d = 27

P(7 \leq x \leq 27) = \frac{27 - 7}{29 - 4} = 0.8

80% probability that x lies between 7 and 27.

​(b) Find the probability that x lies between 6 and 13. ​

So c = 6, d = 13

P(6 \leq x \leq 13) = \frac{13 - 6}{29 - 4} = 0.28

28% probability that x lies between 6 and 13.

(c) Find the probability that x lies between 9 and 20.

​So c = 9, d = 20

P(9 \leq x \leq 20) = \frac{20 - 9}{29 - 4} = 0.44

44% probability that x lies between 9 and 20.

(d) Find the probability that x lies between 11 and 18.

So c = 11, d = 18

P(11 \leq x \leq 18) = \frac{18 - 11}{29 - 4} = 0.28

28% probability that x lies between 11 and 18.

3 0
2 years ago
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