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NISA [10]
3 years ago
7

“Your salary is $25,000 and you will be receiving a 2.5% pay increase this year. What will your new salary be?”

Mathematics
1 answer:
Naddika [18.5K]3 years ago
5 0
If your current salary is the 100%, and you get a 2.5% increase, that means the new salary would be 102.5% of 25,000. This percentage could also be written as 1.025, which you would multiply to 25,000 to get your new salary.

1.025 · 25,000 = 25,625

Therefore, your new salary would be $25,625
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If x2=4(5-1) what is the value of x
Deffense [45]
X2=4(5-1)
x2=4(4)
x2=16
x=4

Check: 4 squared (4 times 4) equals 16. When you square a number, you multiply the number by itself.
5 0
3 years ago
3 n-5 An even ineger, what is the next larger consecutive even integer
Sliva [168]

Answer:

B. n-3

Step-by-step explanation:

If x is an even integer, the next consecutive even integer = x + 2

Since (n-5) is even, the next consecutive even integer = (n-5) + 2 = n-3

8 0
2 years ago
A neighborhood swimming pool is the shape of a rectangular prism the pool measures 30 feet in length and 18 feet in width and ha
lesya [120]

Answer:

15,120 gallons of water

Step-by-step explanation:

to find the volume, your equation is

v=length * width * height

v=30*18*4=2160 feet cubed

2160*7=15120

6 0
2 years ago
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6 0
3 years ago
A physics exam consists of 9 multiple-choice questions and 6 open-ended problems in which all work must be shown. If an examinee
katrin [286]

Answer: A) 1260

Step-by-step explanation:

We know that the number of combinations of n things taking r at a time is given by :-

^nC_r=\dfrac{n!}{(n-r)!r!}

Given : Total multiple-choice questions  = 9

Total open-ended problems=6

If an examine must answer 6 of the multiple-choice questions and 4 of the open-ended problems ,

No. of ways to answer 6 multiple-choice questions

= ^9C_6=\dfrac{9!}{6!(9-6)!}=\dfrac{9\times8\times7\times6!}{6!3!}=84

No. of ways to answer 4 open-ended problems

= ^6C_4=\dfrac{6!}{4!(6-4)!}=\dfrac{6\times5\times4!}{4!2!}=15

Then by using the Fundamental principal of counting the number of ways can the questions and problems be chosen = No. of ways to answer 6 multiple-choice questions x No. of ways to answer 4 open-ended problems

= 84\times15=1260

Hence, the correct answer is option A) 1260

5 0
3 years ago
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