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ohaa [14]
3 years ago
6

Binda is working on an art project that requires 32 feet of ribbon. She has 17 1/2 feet of ribbon, but needs to purchase more ri

bbon to have enough to finish her art project. All of the ribbon will be cut into piece that are 1/4 foot long. Write and solve an equation that can be used to determine the number of feet of ribbon, x, that Binda needs to purchase to finish her art. How many 1/4 foot pieces of ribbon can Binda make from all 32 feet of ribbon?
Mathematics
2 answers:
MatroZZZ [7]3 years ago
8 0

Answer:

x + 17.5 = 32 (subtract 17.5 from 32 to get your answer)

14.5 feet of ribbon Binda needs to purchase

32 / 0.25 = 128 pieces of 1/4 foot ribbon

Step-by-step explanation:

Dafna11 [192]3 years ago
3 0

Answer:

x + 17.5 = 32 (subtract 17.5 from 32 to get your answer)

14.5 feet of ribbon Binda needs to purchase

32 / 0.25 = 128 pieces of 1/4 foot ribbon

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lara31 [8.8K]

Answer:

SE=\sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.35 (1-0.35)}{100}}=0.048

If we replace the values obtained we got:

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Step-by-step explanation:

Notation and definitions

X=35 number of people that agree.

n=100 random sample taken

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p true population proportion of peopl that agree

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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The population proportion have the following distribution

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Solution to the problem

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical value would be given by:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The confidence interval for the mean is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

The standard error is given by:

SE=\sqrt{\frac{\hat p (1-\hat p)}{n}}=\sqrt{\frac{0.35 (1-0.35)}{100}}=0.048

If we replace the values obtained we got:

0.35 - 1.96\sqrt{\frac{0.35(1-0.35)}{100}}=0.257

0.42 + 1.96\sqrt{\frac{0.42(1-0.42)}{150}}=0.443

The 95% confidence interval would be given by (0.257;0.443)

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